Answer:
4
Step-by-step explanation:
The question says that restaurants often slip takeout menus under Maura's apartment door. So far, Maura has collected 15 menus, including 3 for Chinese food. Considering this data, we were asked to find out how many of the next 20 menus slipped under Maura's door should you expect to be from Chinese restaurants?
---Since Maura has collected 3 Chinese menus from a combuned total of 15 various menus,we can estimate the number of combined/total menus that she has to receive in order to be able to have access to a single Chinese menu.
--- For every 15 menus,3 Chinese menus are included.That means that 15/3 = 5 menus.
For every 5 menus,there is a Chinese menu
--- To estimate the number of chinese menus available to Maura after 20 different menus was slipped under her apartment door.
Since that for every 5 menus,there is a Chinese menu.The number of Chinese menus in 20 combined menus is
15/20 = 3/x
Cross multiply and we have
60 = 15x
X = 60/15
X = 4
The number of Chinese menus in 20 combined menus is 4
Answer:
21 vowels.....15 consonants.......added = 36 tiles
probability of first picking a consonant : 15/36 reduces to 5/12
replacing it...
probability that second pick is a vowel : 21/36
probability of both : 5/12 * 21/36 = 105 / 432 reduces to 35/144 <===
Step-by-step explanation:
A. in order to keep the cards, the sum must be > 0. If the first card is negative the second card must be > the negative of of the same card.
example: 0.3 + -0.2 = 0.1
-0.2 is > -0.3
B. The card drawn is a -0.2. Same solution as (A) the second card must be > the negative of the card drawn. So she must draw > 0.2.
(0.5, 0.4, 0.3)
C. The card drawn is a -0.2. If the cards have to be put back due to negative sum, he drew a second card <0.2. This solution is the reverse of (B) except you discount 0.2 because this give a zero sum, not negative. (-0.5, -0.4, -0.3, -0.2, -0.1, 0.1).
<em>Answer:</em>
A. She should reject H0 : µ = 72 and accept Ha : µ < 72
<em>Step-by-step explanation:</em>
Just took it on edge