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poizon [28]
2 years ago
6

According to a certain​ country's department of​ education, 39.4​% of​ 3-year-olds are enrolled in day care. What is the probabi

lity that a randomly selected​ 3-year-old is enrolled in day​ care?
Mathematics
1 answer:
SCORPION-xisa [38]2 years ago
7 0

Answer:

0.394

Step-by-step explanation:

Given:

Percent of 3 year-olds enrolled in daycare = 39.4%

The above statement means that if the total number of 3 year-olds is 100, then out of the 100 persons aged 3 years, the number of persons enrolled in a daycare is 39.4.

Now, probability of an event is the ratio of the favourable outcomes for that event to the total number of outcomes.

Here, the favourable number of outcomes is the number of persons aged 3 years enrolled in a daycare which is equal to 39.4.

The total number of outcomes is the total number of 3 year-olds which is 100.

Therefore, the probability that a randomly selected​ 3-year-old is enrolled in day​care is given as:

P(enrolled)=\frac{39.4}{100}=0.394

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Suppose that a local TV station conducts a survey of a random sample of 120 registered voters in order to predict the winner of
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Answer:

a) The 99% CI for the true proportion of voters who prefer the Republican candidate is (0.3658, 0.6001). This means that we are 99% sure that the true population proportion of all voters who prefer the Republican candidate is (0.3658, 0.6001).

b) The upper bound of the confidence interval is above 0.5 = 50%, which meas that the candidate can be confidence of victory.

Step-by-step explanation:

Question a:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

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Sample of 120 registered voters in order to predict the winner of a local election. The Democrat candidate was favored by 62 of the respondents.

So 120 - 62 = 58 favored the Republican candidate, so:

n = 120, \pi = \frac{58}{120} = 0.4833

99% confidence level

So \alpha = 0.01, z is the value of Z that has a p-value of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.  

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The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4833 + 2.575\sqrt{\frac{0.4833*0.5167}{120}} = 0.6001

The 99% CI for the true proportion of voters who prefer the Republican candidate is (0.3658, 0.6001). This means that we are 99% sure that the true population proportion of all voters who prefer the Republican candidate is (0.3658, 0.6001).

b. If a candidate needs a simple majority of the votes to win the election, can the Republican candidate be confident of victory? Justify your response with an appropriate statistical argument.

The upper bound of the confidence interval is above 0.5 = 50%, which meas that the candidate can be confidence of victory.

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2 years ago
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