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zhannawk [14.2K]
3 years ago
5

2 The solution to the equation x2 - 6x = 0 is 1) 0, only 2) 6, only 3) 0 and 6

Mathematics
1 answer:
Dima020 [189]3 years ago
8 0
1) o, only.............
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HELP THIS IS TIMED !!!!
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Answer:

C

Step-by-step explanation:

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3 years ago
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Can you please help me with the question the link is down below
Shkiper50 [21]

Answer:

output = 9

Step-by-step explanation:

add 5 to the input to obtain output

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7 0
2 years ago
Please help, I have to do this online so I’m getting stuck
Ostrovityanka [42]

Answer:

Function p is a quadratic function

Step-by-step explanation:

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5 0
4 years ago
Can someone explain the answer to this problem? Answer: 6 in.
lana [24]
24 cubes, each 8 cubic inches, meaning each 2 inches on a side.  So the dimensions must be even to fit cubes exactly.  Our box with 9 inches is really only effectively 8 inches because that extra inch doesn't help us fit another cube.  

So our total volume:

24 \times 8 = (8)(4)h

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7 0
3 years ago
Find the derivative of<br> <img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20%5Cfrac%7B6%7D%7Bx%7D%20" id="TexFormula1" titl
aev [14]
f'(x_0)=\lim\limits_{h\to0}\dfrac{f(x_0+h)-f(h)}{h}=\lim\limits_{x\to x_0}\dfrac{f(x)-f(x_0)}{x-x_0}\\\\f(x)=\dfrac{6}{x};\ x_0=2\\\\subtitute\\\\f'(2)=\lim\limits_{x\to2}\dfrac{\frac{6}{x}-\frac{6}{2}}{x-2}=\lim\limits_{x\to2}\dfrac{\frac{6}{x}-3}{x-2}=\lim\limits_{x\to2}\dfrac{\frac{6-3x}{x}}{x-2}=\lim\limits_{x\to 2}\dfrac{6-3x}{x(x-2)}\\\\=\lim\limits_{x\to2}\dfrac{-3(x-2)}{x(x-2)}=\lim\limits_{x\to2}\dfrac{-3}{x}=-\dfrac{3}{2}=-1.5\\\\\\An swer:\boxed{f'(2)=-1.5}
8 0
3 years ago
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