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natita [175]
1 year ago
12

Josiah kept track of how many songs of each genre were played in an hour from his MP3 player. The counts are displayed in the ta

ble below. He has a total of 1,500 songs on his player. Josiah predicted the number of rock songs on his MP3 player to be 300 songs. Which statements about his solution are true? Select three choices.
Josiah’s Music
Sample 1
Sample 2
R & B
5
R & B
4
Pop
4
Pop
3
Classical
3
Classical
5
Jazz
2
Jazz
4
Rock
6
Rock
4

Josiah’s work:

StartFraction 10 over 20 EndFraction = StartFraction x over 1,500 EndFraction. StartFraction 10 times 30 over 20 times 30 EndFraction = StartFraction x over 1,500 EndFraction. 300 = x.
He should have found the average of the number of rock songs by averaging 4 and 6 to get 5.
He did not multiply the numerator and denominator by the correct number to equal 1,500.
His answer will be one-half of what he got because he did not divide 10 by 2 when setting up the proportion.
He can only solve the proportion by multiplying the numerator and denominator by a common multiple.
He should have multiplied the numerator and denominator by 75, not 30, because 20 times 75 = 1,500.
Mathematics
1 answer:
german1 year ago
7 0

Based on the number of songs in each genre that Josiah listened to, the statements about his solution that are true are:

  • He should have found the average of the number of rock songs by averaging 4 and 6 to get 5.
  • He did not multiply the numerator and denominator by the correct number to equal 1,500.
  • He should have multiplied the numerator and denominator by 75, not 30, because 20 times 75 = 1,500.

<h3>What did Josiah do wrong?</h3>

To find the average of the number of rock songs, he should have taken the average of rock songs he listened to which were 4 and 6:

= (4 + 6) / 2

= 5

Because he has a total of 1,500 songs on his player, he should have multiplied both the numerator and denominator by a number that would lead to 1,500 which is 75 and not 30.

Find out more on averages at brainly.com/question/13832161.

#SPJ1

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Answer:

The conditions for use of the normal model to represent the distribution of sample proportion are not met. He should increase the sample size until the conditions are met.

If the test is done anyway, the null hypothesis failed to be rejected.

The conclusion is taht there is not enough evidence to support the claim that the percentage is lower in this district.

Step-by-step explanation:

The conditions for use of the normal model to represent the distribution of sample proportion are not met, as the affirmative responses are less than 10.

np=80*0.1=8

If the test of hypothesis is done as if the conditiones were met, we know that the claim is that  the percentage is lower in this district.

Then, the null and alternative hypothesis are:

H_0: \pi=0.173\\\\H_a:\pi

The significance level is 0.05.

The sample has a size n=80.

The sample proportion is p=0.1.

 

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.173*0.827}{80}}\\\\\\ \sigma_p=\sqrt{0.001788}=0.042

Then, we can calculate the z-statistic as:

z=\dfrac{p-\pi+0.5/n}{\sigma_p}=\dfrac{0.1-0.173+0.5/80}{0.042}=\dfrac{-0.067}{0.042}=-1.578

This test is a left-tailed test, so the P-value for this test is calculated as:

P-value=P(z

As the P-value (0.057) is greater than the significance level (0.05), the effect is  not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that  the percentage is lower in this district.

7 0
3 years ago
In hopes of encouraging healthier snacks at school, Zack brought in a tray of carrot sticks and apple slices to share. The tray
Alex787 [66]

Answer:

48% were carrot sticks.

52% were apple slices.

Step-by-step explanation:

Given that:

Total number of snacks in the tray = 25

Number of carrot sticks = 12

Number of apple slices = 25 - 12 = 13

Percent of carrot sticks = \frac{Number\ of\ carrot\ sticks}{Total\ Number}*100

Percent of carrot sticks= \frac{12}{25}*100

Percent of carrot sticks = 0.48 * 100 = 48%

Percent of apple slices = \frac{13}{25}*100

Percent of apple slices = 52%

Hence,

48% were carrot sticks.

52% were apple slices.

6 0
3 years ago
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