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natita [175]
1 year ago
12

Josiah kept track of how many songs of each genre were played in an hour from his MP3 player. The counts are displayed in the ta

ble below. He has a total of 1,500 songs on his player. Josiah predicted the number of rock songs on his MP3 player to be 300 songs. Which statements about his solution are true? Select three choices.
Josiah’s Music
Sample 1
Sample 2
R & B
5
R & B
4
Pop
4
Pop
3
Classical
3
Classical
5
Jazz
2
Jazz
4
Rock
6
Rock
4

Josiah’s work:

StartFraction 10 over 20 EndFraction = StartFraction x over 1,500 EndFraction. StartFraction 10 times 30 over 20 times 30 EndFraction = StartFraction x over 1,500 EndFraction. 300 = x.
He should have found the average of the number of rock songs by averaging 4 and 6 to get 5.
He did not multiply the numerator and denominator by the correct number to equal 1,500.
His answer will be one-half of what he got because he did not divide 10 by 2 when setting up the proportion.
He can only solve the proportion by multiplying the numerator and denominator by a common multiple.
He should have multiplied the numerator and denominator by 75, not 30, because 20 times 75 = 1,500.
Mathematics
1 answer:
german1 year ago
7 0

Based on the number of songs in each genre that Josiah listened to, the statements about his solution that are true are:

  • He should have found the average of the number of rock songs by averaging 4 and 6 to get 5.
  • He did not multiply the numerator and denominator by the correct number to equal 1,500.
  • He should have multiplied the numerator and denominator by 75, not 30, because 20 times 75 = 1,500.

<h3>What did Josiah do wrong?</h3>

To find the average of the number of rock songs, he should have taken the average of rock songs he listened to which were 4 and 6:

= (4 + 6) / 2

= 5

Because he has a total of 1,500 songs on his player, he should have multiplied both the numerator and denominator by a number that would lead to 1,500 which is 75 and not 30.

Find out more on averages at brainly.com/question/13832161.

#SPJ1

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