I believe it would be the first option.
Answer:
not sure but i think it is
+ × + = +
- × - = +
- × + = +
+ ×- = -
Answer:
a^3-b^3
Step-by-step explanation:
(a−b)(a2+ab+b2)
=(a+−b)(a2+ab+b2)
=(a)(a2)+(a)(ab)+(a)(b2)+(−b)(a2)+(−b)(ab)+(−b)(b2)
=a3+a2b+ab2−a2b−ab2−b3
=a3−b3
Combinations = n! / (n - r)! r!

In this case:
n = 4
r = 3
Combinations = 4! /(4-3)! 3! = 24/(1)(6) = 24/6 = 4
Answer:
4 arrangements