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PilotLPTM [1.2K]
2 years ago
13

Choice 3: Kyra makes $700.00 a week in her job. She did such a great job this week that she is going to get a 15% raise next wee

k. How much will her raise be?
Please help and this is a Percentage problem :)
Mathematics
1 answer:
nikklg [1K]2 years ago
5 0

Answer:

15/100 x 700 = 105

Step-by-step explanation:

Consider 15% as 15 because you always consider a percent out of 100, you can remember by the word 'cent' meaning 100.

You need to FIRST find out what the percentage is OF whenever coming across these types of problems.

And the keyword 'of' means to multiply.

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C = 100g + 50

Step-by-step explanation:

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2 years ago
Math help please, thx
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The answer is radical 9
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Find the ordered pair (x,y) that is a solution to the equation.
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Answer:

☑ (¼, 0)

Step-by-step explanation:

{ \tt{4x - y = 1}}

» Assume y is zero:

{ \tt{4x  - 0 = 1}} \\ { \tt{4x = 1}} \\ { \tt{x =  \frac{1}{4} }}

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2 years ago
What is the greatest common factor of 44c^5, 22c^3 and 11c^4
Alexxandr [17]

\text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3

<em><u>Solution:</u></em>

Given that, we have to find the greatest common factor of 44c^5, 22c^3 , 11c^4

The greatest number that is a factor of two (or more) other numbers.

When we find all the factors of two or more numbers, and some factors are the same ("common"), then the largest of those common factors is the Greatest Common Factor

\underline{\text{ GCF of } 44c^5, 22c^3 , 11c^4 :}

First find the GCF of numbers and then find the GCF of variables and then multiply them together

<em><u>Step 1: GCF of 44, 22 and 11</u></em>

The factors of 11 are: 1, 11

The factors of 22 are: 1, 2, 11, 22

The factors of 44 are: 1, 2, 4, 11, 22, 44

11 is the greatest factor that is common in above three list

Then the greatest common factor is 11

\text{ Step 2: GCF of }c^5, c^3 , c^4

c^5 = c^3 \times c^2\\\\c^3 = c^2 \times c^1 \text{ or } c^3\\\\c^4 = c^3 \times c^1

Thus the greatest common factor is c^3

Step 3: Multiply the GCF of 44, 22, 11 and GCF of c^5, c^3 , c^4

\text{ GCF of } 44c^5, 22c^3 , 11c^4 = 11 \times c^3 = 11c^3

Thus \text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3

8 0
3 years ago
A jeweler is making a triangular pendant. He has two sides of length 23 mm and 31 mm. What are the
denis-greek [22]

Answer:

38.60mm

Step-by-step explanation:

Step one:

Given data

We are given that the dimension of the triangles are length 23 mm and 31 mm

Let us assume that the triangle is a right angle triangle

Step two:

Applying the Pythagoras theorem we can find the third as

z^2= x^2+y^2\\\\z^2= 31^2+23^2\\\\z^2= 961+529\\\\z^2= 1490\\\\

square both sides

z= √ 1490

z= 38.60mm

Hence a possible dimension of the third side is 38.60mm

3 0
3 years ago
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