Solve for x over the real numbers:
4 x^4 + 31 x^3 - 4 x^2 - 89 x + 22 = 0
The left hand side factors into a product with three terms:
(x + 2) (4 x - 1) (x^2 + 6 x - 11) = 0
Split into three equations:
x + 2 = 0 or 4 x - 1 = 0 or x^2 + 6 x - 11 = 0
Subtract 2 from both sides:
x = -2 or 4 x - 1 = 0 or x^2 + 6 x - 11 = 0
Add 1 to both sides:
x = -2 or 4 x = 1 or x^2 + 6 x - 11 = 0
Divide both sides by 4:
x = -2 or x = 1/4 or x^2 + 6 x - 11 = 0
Add 11 to both sides:
x = -2 or x = 1/4 or x^2 + 6 x = 11
Add 9 to both sides:
x = -2 or x = 1/4 or x^2 + 6 x + 9 = 20
Write the left hand side as a square:
x = -2 or x = 1/4 or (x + 3)^2 = 20
Take the square root of both sides:
x = -2 or x = 1/4 or x + 3 = 2 sqrt(5) or x + 3 = -2 sqrt(5)
Subtract 3 from both sides:
x = -2 or x = 1/4 or x = 2 sqrt(5) - 3 or x + 3 = -2 sqrt(5)
Subtract 3 from both sides:
Answer: x = -2 or x = 1/4 or x = 2 sqrt(5) - 3 or x = -3 - 2 sqrt(5)
No i don,t argee because a factor is a bunch of numbers and a divisor is a part of a division problem
Answer:
C. x=-48
Step-by-step explanation:
x/4=-12
multiply both sides by 4
4x/4=4 (-12)
simplify
x=-48
Where's the figure? I can't exactly solve this question without knowing how the figure looks like. So put a picture of the figure and then I'll try to answer your question. :)
Side x side=area of a square
s^2=169
s= square root of 169
s=13
D.
Hope this helps.
