Answer:
ummmmm panda express ig
Step-by-step explanation:
im just in the mood for chinese food rn lol
Answer:
x=1, x=4
Step-by-step explanation:
Answer:
6
Step-by-step explanation:
G,C,P
C,P,G
P,G,C
G,P,C
P,C,G
C,G,P
Since ABCD is a parallelogram, the opposite sides will be parallel and equal,
![\begin{gathered} AB=CD \\ BC=AD \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20AB%3DCD%20%5C%5C%20BC%3DAD%20%5Cend%7Bgathered%7D)
Consider that AC acts as a transversal to the parallel lines AB and CD, so we can write,
![\begin{gathered} \angle CAD=\angle ACB\text{ (Alternate Interior Angles)} \\ BC=AD\text{ (Opposite sides of parallelogram)} \\ \angle ADB=\angle CBD\text{ (Alternate Interior Angles)} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Cangle%20CAD%3D%5Cangle%20ACB%5Ctext%7B%20%28Alternate%20Interior%20Angles%29%7D%20%5C%5C%20BC%3DAD%5Ctext%7B%20%28Opposite%20sides%20of%20parallelogram%29%7D%20%5C%5C%20%5Cangle%20ADB%3D%5Cangle%20CBD%5Ctext%7B%20%28Alternate%20Interior%20Angles%29%7D%20%5Cend%7Bgathered%7D)
So by the ASA criteria, the triangle AED is congruent to the triangle CEB,
Then the corresponding parts of the triangles will be equal,
![\begin{gathered} AE=CE \\ BE=DE \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20AE%3DCE%20%5C%5C%20BE%3DDE%20%5Cend%7Bgathered%7D)
Hence Proved.
Answer:
To solve for the volume of a sphere, you must first know the equation for the volume of a sphere.
V=43(π)(r3)
In this equation, r is equal to the radius. We can plug the given radius from the question into the equation for r.
V=43(π)(123)
Now we simply solve for V.
V=43(π)(1728)
V=(π)(2304)=2304π
Answer is 2304