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Ronch [10]
3 years ago
8

Which of the equations below could be the equation to the parabola

Mathematics
1 answer:
iren [92.7K]3 years ago
7 0
I think the answer is a
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The diameter of a circle is 4 cm. Which equation can be used to find its circumference?
Leya [2.2K]

Answer:

pi times 4

Step-by-step explanation:

Circumference: pi times diameter (pi)(d) or pi times 2 times the radius (pi)(2r)

5 0
3 years ago
Read 2 more answers
3. Define a variable, write an equation, and solve the problem. Carla began a
faust18 [17]

Answer:

Carla has been running 7 miles each day for 13 days.

Step-by-step explanation:

Carla ran 3 miles on her first day, 5 miles on her second day and then 7 miles each day onward.

Let the number of days she ran 7 miles each day = x

Total distance run by Carla = 3 + 5 + 7(x)

                                             = 8 + 7x

If her log book shows that she has run total distance = 99 miles

Equation representing her total run will be,

8 + 7x = 99

7x = 99 - 8

7x = 91

x = \frac{91}{7}

x = 13 days

Therefore, Carla has been running 7 miles each day for 13 days.

3 0
3 years ago
The radius of the circle on a basketball court is 6 ft. What are the approximate circumference and area of the circle?
Andrei [34K]

ANSWER:

Circumference= 37.7

Area= 113.1

5 0
3 years ago
Please help. I'm stuck.
Bezzdna [24]
The root \sqrt{10} can be converted into the power 10^{ \frac{1}{2} }. Therefore we can rewrite the problem as (10^{ \frac{1}{2} } )^ {\frac{3}{4} x} and then follow the exponent rules about a power to a power, multiplying 1/2 and 3/4 together.

Thus the problem becomes 10^{\frac{3}{8}x}, which then can be turned into \sqrt[8]{10} ^{3x}, making the last option our answer.

4 0
3 years ago
Suppose that two teams play a series of games that ends when one of them has won ???? games. Also suppose that each game played
Musya8 [376]

Answer:

(a) E(X) = -2p² + 2p + 2; d²/dp² E(X) at p = 1/2 is less than 0

(b) 6p⁴ - 12p³ + 3p² + 3p + 3; d²/dp² E(X) at p = 1/2 is less than 0

Step-by-step explanation:

(a) when i = 2, the expected number of played games will be:

E(X) = 2[p² + (1-p)²] + 3[2p² (1-p) + 2p(1-p)²] = 2[p²+1-2p+p²] + 3[2p²-2p³+2p(1-2p+p²)] = 2[2p²-2p+1] + 3[2p² - 2p³+2p-4p²+2p³] =  4p²-4p+2-6p²+6p = -2p²+2p+2.

If p = 1/2, then:

d²/dp² E(X) = d/dp (-4p + 2) = -4 which is less than 0. Therefore, the E(X) is maximized.

(b) when i = 3;

E(X) = 3[p³ + (1-p)³] + 4[3p³(1-p) + 3p(1-p)³] + 5[6p³(1-p)² + 6p²(1-p)³]

Simplification and rearrangement lead to:

E(X) = 6p⁴-12p³+3p²+3p+3

if p = 1/2, then:

d²/dp² E(X) at p = 1/2 = d/dp (24p³-36p²+6p+3) = 72p²-72p+6 = 72(1/2)² - 72(1/2) +6 = 18 - 36 +8 = -10

Therefore, E(X) is maximized.

6 0
3 years ago
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