Pleaseeeeeeeeeeeee help me!!!!!

Auto insurance Insurance companies collect annual pay-ments from drivers in exchange for paying for the cost of accidents.a) Why

Igoryamba

Answer:

Step-by-step explanation:

a) Because you are only receiving $1500 and in exchange you would have to cover for this accident damage in the next year, which could be up to hundred of thousands of dollar. Sure there's a chance the your neighbor might drive safely, but the odds are far more in his favor than yours.

b) The insurance company collect payments from hundred of thousands buyers, making their cash flow up to tens of million dollar. Sure the expected value of accidents might be high but as a company they surely have capital to cover a handful of cases, if their calculation done right.

8 0

4 years ago

What is <img src="https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B3%7D%20%2A%2081" id="TexFormula1" title="\frac{2}{3} * 81" alt="\frac

Vaselesa [24]

Hello!

Answer: ⇒⇒⇒⇒⇒⇒⇒ =54

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Step-by-step explanation:

First you had to convert element to fraction.

$\frac{2}{3}*\frac{81}{1}$

Then you had to cross out by the common factor of 3.

$\frac{2}{1}=\frac{27}{1}$

Multiply by the fraction.

$\frac{2*27}{1*1}$

Multiply by the number.

$2*27=54$

$=\frac{54}{1*1}$

Again multiply by the number.

$1*1=1$

$=\frac{54}{1}$

Apply rule.

$\frac{54}{1}=54$

54 is the right answer.

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Hope this helps!

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Have a great day!

-Charlie

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4 0

3 years ago

What is the probability of not picking a red face card when you draw a card at random from a pack of 52 cards?

aniked [119]

Answer:

3/13

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Which answer best describes the complex zeros of the polynomial function?

marysya [2.9K]

Answer-

D. The function has one real zero and two nonreal zeros. The graph of the function intersects the x-axis at exactly one location.

Solution-

The given polynomial is,

$f(x)=x^3-x^2+6x-6$

The zeros of the polynomials are,

$\Rightarrow f(x)=0$

$\Rightarrow x^3-x^2+6x-6=0$

$\Rightarrow x^2(x-1)+6(x-1)=0$

$\Rightarrow (x^2+6)(x-1)=0$

$\Rightarrow (x^2+6)=0,(x-1)=0$

$\Rightarrow x=\sqrt{-6},\ x=1$

$\Rightarrow x=1,\ \pm \sqrt6i$

Therefore, this function has only one real zero i.e 1 and two nonreal zeros i.e ±√6i . The graph of the function intersects the x-axis at exactly one location i.e at x = 1

3 0

3 years ago

Anyone can help me I would appreciate it

Kisachek [45]

Answer:

This would be shifted down 8 and made 3 times less steep.

Step-by-step explanation:

In order to determine these transformations, we first need to compare the constants at the end. This will determine the up or downward shift. Since the f(x) is 5 and the g(x) is -3, we know that it went down 8.

Next we compare the coefficients of x. Since the f(x) is 6 and the g(x) is 2, we know that it is 3 times less steep.

7 0

3 years ago