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kramer
2 years ago
11

2 meters and 20 centimeters = ? millmeters

Mathematics
1 answer:
Shalnov [3]2 years ago
7 0

2 meters and 20 centimeters =2200 millimeters

millimeters are smaller than centimiters and meters so how is is 40 when 2 meters are 2000 millimeters and 20 centimiters are 200 millimeters

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Find the slope C(-8,-7) and D (13,-1
DaniilM [7]

So you will use slope formula which is m = (y2 -- y1) / (x2 -- x1)

-1 minus -7=6

13 minus -8=21

Remember it changes to a positive Keep,Change,Change

So its 6/21

Or 1/4

Ask questions if you still need help

:)


3 0
3 years ago
What is the slope of the line that passes through the points (9, 1) and (17, 2)
Wewaii [24]

Answer:

C

Step-by-step explanation:

Slope of a line that goes trough the points (x1=9, y1=1) and (x2=17, y2=2)

m= (y2-y1)/(x2-x1) = (2-1) / (17-9) = 1/8

3 0
2 years ago
Simone has 20 bills. One fifth of the bills are hundreds, 1/4 of them are fifties, 1/10 of them are $20s. The rest of the bills
larisa [96]
If Simone has 20 bills, then:

1/5 of 20 = 4 [hundreds]
1/4 of 20 = 5 [fifites]
1/10 of 20 = 2 [$20s]

4 * 100 + 5 * 50 + 2 * 20 = 400 + 250 + 40 = 690 [out of $780]
4 + 5 + 2 = 11 [out of 20 bills]

So now we can easily find out she had 9 bills of tens - because 20 - 11 = 9 or because (780 - 690) ÷ 10 = 90 ÷ 10 = 9.
5 0
3 years ago
use the information provided to write the standard form equation of each hyperbola vertices:(4,14), (4,-10) foci: (4,15), (4,-11
Evgen [1.6K]
So... if you notice the picture below, based on the given vertices, is a hyperbola with a vertical traverse axis

meaning for the equation, the fraction with the "y" variable is the positive fraction, thus \bf \cfrac{(y-{{ k}})^2}{{{ a}}^2}-\cfrac{(x-{{ h}})^2}{{{ b}}^2}=1

so... what' the point h,k for the center?  well, just take a peek at the graph, the center is half-way between both vertices, that's h,k

what's the "a" component or the traverse axis... well, is the distance from one vertex to the center, notice the picture, notice how many units from either vertex to the center, that's "a"

now.. what's "b"?  well, "b" comes from the conjugate axis, or the other runnning over the x-axis   hmm the smaller one in this case.... well, we dunno what "b" is

however, we know the distance from either focus, to the center of the hyperbola, and that distance "c", is  \bf c=\sqrt{a^2+b^2}

notice the picture, notice the distance from either focus to the center, that's the distance "c", thus  \bf c=\sqrt{a^2+b^2}\implies c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b

that'd be "b"

bearing in mind that   \bf \cfrac{(y-{{ k}})^2}{{{ a}}^2}-\cfrac{(x-{{ h}})^2}{{{ b}}^2}=1
\qquad 
\begin{cases}
center= ({{ h}},{{ k}})\\\\ b=\sqrt{c^2-a^2}
\end{cases}

8 0
3 years ago
Triangle ABC is similar to Triangle FGH. What is the value of x in centimeters?
EleoNora [17]

<u>Given</u>:

Given that the triangle ABC is similar to triangle FGH.

We need to determine the value of x.

<u>Value of x:</u>

Since, the triangles are similar, then their sides are proportional.

Thus, we have;

\frac{AC}{FH}=\frac{AB}{GF}=\frac{BC}{GH}

Let us consider the proportion \frac{AB}{GF}=\frac{BC}{GH} to determine the value of x.

Substituting AB = 9 cm, GF = 13.5 cm, BC = 15 cm and GH = x, we get;

\frac{9}{13.5}=\frac{15}{x}

Cross multiplying, we get;

9x=15 \times 13.5

9x=202.5

 x=22.5 \ cm

Thus, the value of x is 22.5 cm

Hence, Option F is the correct answer.

8 0
3 years ago
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