#11..................................
1 answer:
Answer:
54.7 ft
Step-by-step explanation:
The question given above can be summarised in the attached photo.
u = Initial distance from the building
x = final distance from the building
y = distance moved from the initial point.
First, we shall determine the value of 'u'. This can be obtained as follow:
Opposite = 200 ft
Adjacent = u
Angle θ = 45°
Tan θ = Opposite / Adjacent
Tan 45 = 200 / u
Cross multiply
u × Tan 45 = 200
u × 1 = 200
u = 200 ft
Next, we shall determine the value of 'x'. This can be obtained as follow:
Opposite = 200 ft
Adjacent = x
Angle θ = 54°
Tan θ = Opposite / Adjacent
Tan 54 = 200 / x
Cross multiply
x × Tan 54 = 200
x × 1.3764 = 200
Divide both side by 1.3764
x = 200 / 1.3764
x = 145.3 ft
Finally, we shall determine the value of 'y'. This can be obtained as follow:
u = 200 ft
x = 145.3 ft
y =?
u = x + y
200 = 145.3 + y
Collect like terms
y = 200 – 145.3
y = 54.7 ft
Thus, the person walked 54.7 ft
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Answer:
16 Unit
Step-by-step explanation:
With P(-2,1) , Q(6,1) , R(4,-3) , S(4,1) , the triangle and its altitude look like the one attached in figure.
The length of base PQ is the difference in the x-coordinates of P and Q,
6-(-2)=6+2=8 , because the y-coordinates are both the same as 1.
The height (the length of altitude RS is the difference in the y-coordinates of R and S,
1-(-3)=1+3=4 , because the y-coordinates are both the same as 4 .
The area is
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