Answer:
21 ft by 66 ft
Step-by-step explanation:
From the question,
P = 2(L+W)............... Equation 1
Where P = Perimeter of the playing Field, L = Length of the playing Field, W = width of the playing Field.
If the Length of the Field is 45 ft longer than the width,
L = 45+W............ Equation 2
Substitute Equation 2 into equation 1
P = 2(45+W+W)
P = 90+4W............. Equation 3
Given: P = 174 ft.
Substitute into equation 3
174 = 90+4W
4W = 174-90
4W = 84
W = 84/4
W = 21 ft.
Substituting the value of W into equation 2
L = 45+21
L = 66 ft.
Hence the dimensions of the playing field is 21 ft by 66 ft
Step-by-step explanation:
s1 = 300
s2 = s1 × 2 = 300 × 2 = 600
s3 = s2 × 2 = s1 × 2² = 1200
sn = sn-1 × 2 = s1 × 2^(n-1)
s7 = 300 × 2⁶ = 300 × 64 = 19,200
Since ABCD is a parallelogram, the opposite sides will be parallel and equal,
Consider that AC acts as a transversal to the parallel lines AB and CD, so we can write,
So by the ASA criteria, the triangle AED is congruent to the triangle CEB,
Then the corresponding parts of the triangles will be equal,
Hence Proved.
That's an awfully broad question. Could you not be more specific?
A basic example: Suppose you are told that sin theta = 1/2. Solving this equation would require finding the measure of the angle theta. In this case the answer would be "30 degrees," or "pi/6 radians."
The answer would be C) 2x + 10.
Expand ( -3x + 5x + 10 )
Simplify ( 2x + 10 ).
