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Gekata [30.6K]
3 years ago
9

True or false ? why and why not ? 7a + 4 - 2a is equivalent to 7a + -2a + 4

Mathematics
1 answer:
Oxana [17]3 years ago
6 0
True because it’s a diamond Rottweiler
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Please answer clear i need answers now please
Salsk061 [2.6K]

Answer:

The answers would be:

9: $421.54

10: $872

11: $4,706.66

12: $645.83

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5 0
2 years ago
1.) Vivian combined different amounts of white paint, blue paint, and green paint to make 145 milliliters (ml) of paint of a new
Ivahew [28]
So here are the answers to the given questions above:
1. Since the equation is already given, what we are going to do is to solve for x first. 
<span>x + (2x – 10) + 1/2 (2x – 10) = 145
x + (2x -10) + x - 5 = 145
x + 2x + x - 10 - 5 = 145
4x = 145 +10 + 5
4x = 160 <<divide both sides by 4 and we get
x = 40.
Therefore, the amount of white paint is 40ml.
The amount of blue paint is 70ml and the green paint is 35ml.
So the difference between the a</span><span>mounts of white paint and blue paint Vivian combined is 30ml.
2. T</span>he equation of the line that passes through the points (-2, 1) and (1, 10) would be: <span>3x - y = -7, the last option. In order to check, just plug in the given ordered pairs.</span>
3 0
2 years ago
Sin2alpha+cos2alpha-cos6alpha/sin4alpha+2sin²alpha-1<br><br> if alpha is -135°​
balandron [24]

Answer:

=  \frac{\sin(2 \alpha )  +  \cos(2 \alpha )  -  \cos(6 \alpha ) }{ \sin(4 \alpha )  + 2 { \sin }^{2}  \alpha  - 1}  \\  =  \frac{ \sin( - 270) +  \cos( - 270)  -  \cos( - 810)  }{ \sin( - 540)  + 2 { \sin }^{2}( - 135) - 1 }  \\  =  \frac{1}{ - 2}  \\  =  - 0.5

5 0
2 years ago
Triangle NMO has vertices at N(−5, 2), M(−2, 1), O(−3 , 3). Determine the vertices of image N′M′O′ if the preimage is reflected
Firdavs [7]

Notice that the reflection is over a line of the form x=constant; in this case, the y-coordinate of the reflected point stays the same while the x-coordinate changes as expressed by the transformation below

\begin{gathered} y\rightarrow y \\ x\rightarrow2a+x \\ where \\ x=a\rightarrow\text{ vertical line} \end{gathered}

Hence, in our case

\Rightarrow(x,y)=(2*-4-x,y)=(-8-x,y)

Transform points N, M, and O accordingly,

\begin{gathered} \Rightarrow N^{\prime}=(-8-(-5),2)=(-8+5,2)=(-3,2) \\ \Rightarrow M^{\prime}=(-8-(-2),1)=(-6,1) \\ \Rightarrow O^{\prime}=(-8-(-3),3)=(-5,3) \end{gathered}<h2>Therefore, the answer is the first option (top to bottom)</h2>

6 0
9 months ago
Write an expression using all six trigonometric functions such that the value of the expression is 3.
iren2701 [21]
The trig functions that you need to deal with are
Sine
Cosine
Tangent
Cotangent
Cosecant
Secant

You need to write a single expression using all six trig functions such that the value of the expression equals 3.

To make this as simple as possible, the first thing I would do is look up the values of these functions and identify which ones are equal to either 1/2 or 1.0 or 2.0

sin(30º) = 1/2
sin(90º) = 1
cos(0º) = 1
cos(60º) = 1/2
tan(45º) = 1
csc(30º) = 2
csc(90º) = 1
sec(0º) = 1
sec(60º) = 2
cot(45º) = 1

If we only had to use three trig functions (sin, cos, tan), one possibility is
tan(45º) + cos(0º)/sin(30º) = 1 + 1/(1/2) = 1 + 2 = 3
noticed how I chose one each of the required functions and the operations so that the result = 3.

Now it is up to you to figure out how to combine all six trig functions so that they equal zero. There are many possibilities for you to choose from..
6 0
2 years ago
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