Ose has 50 coins in a jar. 20% are nickels, 40% are quarters, and the rest are pennies. (6.RP.3c-Benchmark #3)

Mathematics

2 answers:

____ [38]3 years ago

7 0

Answer:

Part A: pennies are 40% of the jar

Part B :

Nickels: 10

Quarters: 20

Pennies: 20

Step-by-step explanation:

Part A: since the nickels and quarters make up 60% of the jar the pennies make up the other 40%.

Part B:

Nickels: 20 percent of 50 (the amount of coins in the jar) is 10

Quarters & Pennies (since they have the same percentage): 40 percent of 50 is 20

cupoosta [38]3 years ago

5 0

Answer:

Part A: 40% are pennies

Part B: NIckels 10, Quarters 20, Pennis 20

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In a random sample of 60 shoppers from a large suburban mall, 36 indicated that they had been to a movie in the past month. In a

ZanzabumX [31]

Answer:

There is no enough statistical evidence to reject the hypothesis that the proportion of suburban mall shoppers who had been to a movie in the same month is the same as the proportion downtown.

Step-by-step explanation:

We have to perform an hypothesis test on the difference of proportions to see if there is enough evidence to reject the null hypothesis.

The null and alternative hypothesis are:

$H_0: \pi_1-\pi_2=0\\\\H_a: \pi_1-\pi_2\neq0$

The significance level is assumed to be α=0.05

The suburban sample has a proportion of

$p_1=36/60=0.6$

The downtown sample has a proportion of

$p_2=31/50=0.62$

The average of proportion is:

$p=\frac{n_1p_1+n_2p_2}{n_1+n_2}=\frac{60*0.60+50*0.62}{60+50}=\frac{67}{110}=0.61$

The standard deviation of the difference of proportions is:

$s_{p1-p2}=\sqrt{\frac{p(1-p)}{n_1} +\frac{p(1-p)}{n_2} } =\sqrt{\frac{0.61*0.39}{60} +\frac{0.61*0.39}{50} }\\\\s_{p1-p2}=\sqrt{0.003965+0.004758}=0.0934$