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3 years ago

9

At a school, each class period is 3/4 hour long. If there are 6 hours of class time in a school day, how many class periods are

there?

2 answers:

Vsevolod [243]3 years ago

7 0

Answer:

34%

Step-by-step explanation:

kompoz [17]3 years ago

5 0

Answer:

2 im thinking this so tell me if i got it wrong

Step-by-step explanation:

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Right triangles 1, 2, 3 are given with all their angle measures

zlopas [31]

Answer:

6.4/7.7 is the ratio

Step-by-step explanation:

The bottom triangle matches the 50 40 90 angle, so the ratio of the triangle length is consistent

- Gage Millar, Algebra 2 tutor

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2 years ago

Differentiate x^2 e^x logx

zimovet [89]

Product rule:

$\dfrac{\mathrm d}{\mathrm dx}(x^2e^x\log x)$

$=\dfrac{\mathrm d(x^2)}{\mathrm dx}e^x\log x+x^2\dfrac{\mathrm d(e^x)}{\mathrm dx}\log x+x^2e^x\dfrac{\mathrm d(\log x)}{\mathrm dx}$

Power rule:

$\dfrac{\mathrm d(x^2)}{\mathrm dx}=2x$

The exponential function is its own derivative:

$\dfrac{\mathrm d(e^x)}{\mathrm dx}=e^x$

Assuming the base of $\log x$ is $e$ , its derivative is

$\dfrac{\mathrm d(\log x)}{\mathrm dx}=\dfrac1x$

But if you mean a logarithm of arbitrary base $b$ , we have

$y=\log_bx\implies x=b^y=e^{y\ln b}\implies1=e^{y\ln b}\ln b\dfrac{\mathrm dy}{\mathrm dx}$

$\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{e^{-y\ln b}}{\ln b}=\dfrac1{b^y\ln b}$

$\implies\dfrac{\mathrm d(\log_bx)}{\mathrm dx}=\dfrac1{x\ln b}$

So we end up with

$2xe^x\log x+x^2e^x\log x+\dfrac{x^2e^x}x$

$=xe^x(2\log x+x\log x+1)$

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3 years ago

Which graph represents a function??

SSSSS [86.1K]

Graph D, because no x-value repeats and it passes the vertical line test.

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3 years ago

What is 9 3/4 as a mixed number and a percent?

krok68 [10]

9 3/4 is a mixed number, and to find a percent it has to be a percent of what. 9 3/4 as a percent alone is 975% if that's what they want.

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2 years ago

What is the charge on an object that has 1. 25 * 10 ^-17.

Aliun [14]

Answer: To determine the charge on an object, determine the number of excess protons or excess electrons. Multiply the excess by the charge of an electron or the charge of a proton - 1.6 x 10-19 C.

Step-by-step explanation:

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2 years ago