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GenaCL600 [577]
3 years ago
10

Please help! I'm stuck:(

Mathematics
1 answer:
irina [24]3 years ago
3 0

Answer:

1st graph is Y=1x+0

2nd Graph is Y=-2/1x + 0

Step-by-step explanation:

Your slope is 1 for the 1st graph

Your slope is -2/1 for the second graph

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How do I get this problem started
Vesnalui [34]
So first in a separate sheet of paper you have to look for how many members of fam and friends does Kimberly have. Then write down the amount of money she has in total.
Then subtract 120-36 cause she buys the book.
Which equals. 84
Then you have to subtract 84 from what I said at the beginning
3 0
2 years ago
Given that<br>9^-1/2 = 27^1/4 ÷ 3^x+1<br>Find the exact value of x. ​
nexus9112 [7]

Answer:

Find the exact value using trigonometric identities.

Exact Form: x=34

Decimal Form: x=0.75

Step-by-step explanation:

5 0
3 years ago
WILL GIVE BRANLIEST! pls help thank u sm!! :-) u are all amazing
Andrews [41]

Answer:

C

Step-by-step explanation:

Given

3(x+9)^{\frac{3}{4} } = 24 ( divide both sides by 3 )

(x+9)^{\frac{3}{4} } = 8

Raise both sides to the power of \frac{4}{3}

x + 9 = 8^{\frac{4}{3} } = (\sqrt[3]{8}) ^{4} = 2^{4} = 16 ( subtract 9 from both sides )

x = 7 → C

5 0
3 years ago
Micah bought 2 pens for $0.99 each and a pack of paper for $1.47. She gave the clerk some money and got back $1.55 in change. Ho
kkurt [141]

Answer: a $5 bill

Step-by-step explanation: add everything up together the pens add twice

5 0
2 years ago
Read 2 more answers
(4.1.4) Let X and Y be Bernoulli random variables. Let Z = X + Y. a. Show that if X and Y cannot both be equal to 1, then Z is a
Fynjy0 [20]

Step-by-step explanation:

Given that,

a)

X ~ Bernoulli (p_x) and Y ~ Bernoulli (y_x)

X + Y = Z

The possible value for Z are Z = 0 when X = 0 and Y = 0

and Z = 1 when X = 0 and Y = 1 or when X = 1 and Y = 0

If X and Y can not be both equal to 1 , then the probability mass function of the random variable Z takes on the value of 0 for any value of Z other than 0 and 1,

Therefore Z is a Bernoulli random variable

b)

If X and Y can not be both equal to  1

then,

p_z = P(X=1 or Y=1)\\

p_z = P(X=1)+P(Y=1)-P(=1 and Y =1)

p_z = P(x=1)+P(Y=1)\\\\p_z=p_x+p_y

c)

If both X = 1 and Y = 1 then Z = 2

The possible values of the random variable Z are 0, 1 and 2.

since a  Bernoulli variable should be take on only values 0 and 1 the random variable Z does not have Bernoulli distribution

7 0
3 years ago
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