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coldgirl [10]
3 years ago
14

What is the fraction that is equal to 0.534

Mathematics
2 answers:
Shalnov [3]3 years ago
6 0

Step-by-step explanation:

<em>537</em><em>/</em><em>1</em><em>000</em>

<em>this</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>correct</em><em> </em><em>answer</em><em> </em>

Mandarinka [93]3 years ago
3 0

Answer:

267/500

Step-by-step explanation:

0.534 = 534 / 1000

Simplify to 267/500

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Translate the sentence into an equation.
Marta_Voda [28]

Answer:

Step-by-step explanation:

7x + 6 = 3

If you want to continue to find the value of x, do this:

7x + 6 - 6 = 3 - 6 = -3, or

7x = -3, or

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4 0
2 years ago
You have been asked to design a rectangular box with a square base and an open top. The volume of the box must be 1536cm3. Deter
Katen [24]

Answer:

The dimensions of the box are:

Length = 11.53cm

Breadth = 11.53cm

Height = 11.53cm

Step-by-step explanation:

The volume of the box can be calculated with this formula:

The volume of the box = area of square base X height of the box.

We are given that the length of one side of the square base is = x cm, and its height is h cm.

Area of square base = x^{2}cm^{2}

The surface area of the box will be minimized if the height of the box, is the same as its length. hence, we can take the height of the box to be x cm also.

In this case, the volume of the box will be x^{3}=1536cm^{3}

from this, x =3\sqrt{1536}= 11.53cm

There fore, the box has its length, height, and width all having the same values.

The dimensions of the box are:

Length = 11.53cm

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8 0
3 years ago
Two cones have a radius of 2 cm. The height of one cone is 8 cm. The other cone is 1 4 14 that height. Which of these statements
MAXImum [283]
Hi there!
The correct answer (the statement that is not true): The volume of the smaller cone cannot be determined because it’s height is unknown.
Hope this helps and have a good day :) !
~Angel
4 0
3 years ago
Identify the type of pair of angles labeled as 1 and 2 in the figure.
myrzilka [38]

<em>Hey</em><em>!</em><em>!</em>

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<em>Vertically</em><em> </em><em>opp</em><em>osite</em><em> </em><em>angles</em><em> </em><em>are</em><em> </em><em>always</em><em> </em><em>equal</em><em> </em><em>to</em><em> </em><em>each</em><em> </em><em>other</em><em>.</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em><em>.</em>

7 0
2 years ago
Read 2 more answers
How do you solve each absolute value by graphing
saw5 [17]
Your question answers itself. You solve by graphing.

I like to subtract one side of the equation from the other, so the solutions are where the graph crosses the x-axis (the resulting function value is zero).

It can be useful to find the "turning point" of each absolute value expression (where its value is zero) and graph that and some points on either side.
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