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igomit [66]
3 years ago
9

The maximum heart​ rate, in beats per​ minute, that you should achieve during exercise is 220 minus your​ age, 220 minus a. Your

exercise goal is to improve cardiovascular conditioning. Use the following formulas to answer parts a and b. Lower limit of range Hequalsseven tenths left parenthesis 220 minus a right parenthesis Upper limit of range Hequalsfour fifths ​(220 minus a​) a. What is the lower limit of the heart​ range, in beats per​ minute, for a 43​-year-old with this exercise​ goal? The lower limit of the heart range is nothing beats per minute. ​(Round to the nearest integer as​ needed.)
Mathematics
1 answer:
polet [3.4K]3 years ago
7 0

Answer:

a) Lower limit range = 119.7 ≈ 120

b) Upper limit range = 136.8 ≈ 137

Step-by-step explanation:

Given:

a) Lower limit range = \frac{\textup{7}}{\textup{10}}\times(220-\textup{Age})

Therefore,

For the given person of age 43 years old

substituting the value of age in the above equation, we get

Lower limit range = \frac{\textup{7}}{\textup{10}}\times(220-\textup{49})

or

Lower limit range = 119.7 ≈ 120 beats per minute

b) The upper limit range = \frac{\textup{4}}{\textup{5}}\times(220-\textup{Age})

Therefore,

For the given person of age 43 years old

substituting the value of age in the above equation, we get

Upper limit range = \frac{\textup{4}}{\textup{5}}\times(220-\textup{49})

or

Upper limit range = \frac{\textup{4}}{\textup{5}}\times(220-\textup{49})

or

Upper limit range = 136.8 ≈ 137 beats per minute

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Gala2k [10]

Answer:

6+3=9

Step-by-step explanation:

Evaluando 6+3=9, porque tu tienes que intercambiar x por 3 porque x es 3. Después tu tienes que buscar tu repuesta. Disculpa mi español no es tan bueno escribiendo

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3 years ago
En una fiesta se desea elegir un grupo de 3 personas de entre 6 matrimonios, si dos miembros de la misma pareja no pueden ser el
LenaWriter [7]

Answer:

Hay 160 maneras

Step-by-step explanation:

Para calcular de cuántas maneras se puede seleccionar x elementos de un grupo de n elementos podemos usar la siguiente fórmula:

nCx=\frac{n!}{x!(n-x)!}

Si vas a elegir 3 personas de entre 6 matrimonios y dos miembros de la misma pareja no pueden ser elegidos, entonces podemos decir que se está eligiendo 3 matrimonios y en cada matrimonio se está eligiendo un representante.

Entonces, podemos calcular de cuántas maneras se puede escoger 3 matrimonios de los 6, así:

6C3=\frac{6!}{3!(6-3)!}=20

Adicionalmente, para cada uno de los 3 matrimonios hay 2 opciones para ser representantes. Esto significa que hay 2^3 maneras de escoger representantes en cada una de las 20 formas calculadas anteriormente.

Por lo tanto se puede formar el grupo de 3 personas de 160 maneras diferentes:

20*2^3=160

6 0
3 years ago
Jesuseduardomontiel0 avatar
AlexFokin [52]

WOW JIMMY. THATS A BIG . BIG. BIG. NUT SACK

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.........................................................................................................
erastova [34]

Answer:

I have no clue... I'm very sorry...

Step-by-step explanation:

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Step-by-step explanation:

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