Question

Solve the system of equations below.

Answer 1

Answer:

none

Step-by-step explanation

A. 2x-3y=2

B. 4x-y=10

Okay.

2(7)-3(4)=2 ⇒ 14-12=2

not correct, 4(7)-(4)=10 ⇒ 28-4=24

-----------

2(5)-3(2)= 10-6=4 not 2, incorrect

4(5)-2=10 ⇒20-2=18 incorrect.

Answer A, B, C and D are incorrect. They didn't give you the correct equations or answers. Heres why

-------------------------------------------

A. 2x-3y=2

B. 4x-y=10

1. neither equation contains an isolated variable (aka, y=x+2, y is the isolated variable). However, we can isolate -y in equation B by subtracting -4x on both sides.

Ending up with -y=10-4x

     Now I like to change -y into y and it's very easy. All you need to do is:

     $\frac{-y=10-4x}{-y}$ Remember: $\frac{neg}{neg}=pos, \frac{neg}{pos}=neg, \frac{pos}{neg}=neg,\frac{pos}{pos} =pos$

Ending up with y=-10+4x

2.Now, we can plug the expression (a phrase) -10+4x into equation A as a substitute for y and solve for x.

$2x-3(-10+4x)=2\\ 2x+30-12x=2\\ -10x+30=2\\ -10x+30-30=2-30\\ -10x=-28\\ \frac{-10x}{-10x} =\frac{28}{-10x}\\ x=-2.8$

3. Solve for y.

$2(-2.8)-3y=2\\ -5.6-3y=2\\ -5.6+5.6-3y=2+5.6\\ 3y=7.6\\ \frac{-3y}{-3y}=\frac{7.6}{-3y} \\ y=-2.5333333$

------------------------

No solution

3≠5

----------------------

Infinitely Many Solutions

3=3