Answer:
980,100
Explanation:
let the recessive condition (aa) be represented as q² which is the genotypic frequency = 100/1,000,000 = 0.0001
allelic frequency of a = q = √q² = √0.0001 = 0.01. thus q = 0.01
From the formula p + q = 1 where p is the allelic frequency of A.
since q = 0.01
p = 1 - 0.01 = 0.99. The allelic frequency of A (p) = 0.99
p² = 0.99² = 0.9801. Genotypic frequency of AA= 0.9801
= 0.9801 x 1,000,000 = 980,100 individuals with AA (homozygous normal)
For 2pq genotypic frequency for hetrozygous (Aa).
Using the formula p² + 2pq + q² = 1. Since p² = 0.9801 and q² = 0.0001
2pq = 1 - (p² + q²)
= 1 - (0.9801 + 0.0001)
= 1 - (0.9802)
= 0.0198 = 0.0198 x 1,000,000 = 19,800 individuals with Aa
Explanation:
Its was discovered back in the 1920s, by Dr. Ralph DeBerardinis and Dr. Joshua Rabinowitz that cancer cells prefer not to rely on the citric acid cycle like healthy cells do. Instead, they turn most of their pyruvate (SALT) into lactate, which then releases. Because cancer cells consume so much glucose, they end up producing a lot of lactate.
The Circle of Lactate: How cancer cells can reuse their own waste
by Lara Roach
Feb 13, 2018
To increase the amount of food produced by corn crops, the farmer could select for more cobs on the corn.
Answer:
Robber crabs have more in common with humans than sponges.
Explanation:
Robber crabs have more in common with humans than sponges because sponges don't have tissues. Crabs and humans have specialised tissue.
