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Mashutka [201]
3 years ago
15

Will give brainliest to good answer

Mathematics
1 answer:
kakasveta [241]3 years ago
8 0

Here are some notes i have from some sources i hope these notes will be able to help you achieve the grade you wanted to good luck!

-The bound on error of estimation, B , associated with a confidence interval is (z critical value) ·(standard error of the statistic) . ... Sample Size The sample size required to estimate a population proportion  to within an amount B with 95% confidence is The value of  may be estimated by prior information.

-P-value and margin of error are not same.

-A margin of error tells you how many percentage points your results will differ from the real population value. For example, a 95% confidence interval with a 4 percent margin of error means that your statistic will be within 4 percentage points of the real population value 95% of the time.

-The margin of error determines how reliable the survey is or how reliable the results of the experiment are. ... This is captured in statistics as margin of error. The higher the margin of error, the less likely it is that the results of the survey are true for the whole population.

-Population distribution means the pattern of where people live. World population distribution is uneven. Places which are sparsely populated contain few people. Places which are densely populated contain many people.

These notes are from sources found online not mine If you want the sites just comment and ill give you them!

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You measure 34 backpacks' weights, and find they have a mean weight of 33 ounces. Assume the population standard deviation is 10
Dmitriy789 [7]

Answer:

The maximal margin of error associated with a 99% confidence interval for the true population mean backpack weight is 4.81 ounces

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

So

M = 2.575*\frac{10.9}{\sqrt{34}} = 4.81

The maximal margin of error associated with a 99% confidence interval for the true population mean backpack weight is 4.81 ounces

6 0
3 years ago
Kevin has a spinner that has 10 equal sections and 2 sections of each color—red, blue, green, yellow, and purple. Kevin spins th
IrinaK [193]

Answer:  2nd answer

Step-by-step explanation:

Kevin should have used a 4 in the numerator because there are 2 red sections and 2 green sections.

6 0
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You measure a piece of rope and find its length to be 12m. Find the percent error of this measurement. Round to the nearest hund
guapka [62]
I want to say about 15 %
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he pay a fixed charge of $30 plus $10 per hour to rent the digger work out how much he pays to rent the digger for?
Maslowich
How many hours does he rent it?

Either way, the equation would be 30 + 10x

x is the number of hours he rents the digger.

So for example, if he rented it for say 8 hours

30 + 10(8)
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$110
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Anwser the photo please!<br> Thanks!
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Answer:

(3,1)

Step-by-step explanation:

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