Answer:
y = -4x-21
Step-by-step explanation:
Hi there!
We want to write an equation of the line that passes through (-4, -5) and is parallel to y=-4x-1.
Parallel lines have the same slopes. So let's find the slope of y=-4x-1.
The line is written in the form y=mx+b, where m is the slope and b is the y intercept.
As -4 is in the place of where m should be, -4 is the slope of y=-4x-1.
It's also the slope of the line parallel to that line.
Right now, what we know about the line parallel to y=-4x-1 is that the slope of it is 4 and it passes through the point (-4, -5).
We can substitute those values into the formula for point-slope form, which is 
, where m is the slope and 
is a point.
We can label the values of everything to help us avoid confusion.
m=-4
Now substitute those values into the formula. Note: the formula contains SUBTRACTION, and we have NEGATIVE numbers. Hence,
Now simplify.
On the right side, do the distributive property.
y+5=-4x-16
Subtract 5 from both sides.
<u>y=-4x-21</u>
Hope this helps!
Answer:
Step-by-step explanation:
The first two are incorrect. Only very special n's will work. (Every 10th one for n>0)
Just call A and B incorrect.
400o = 360 + 40
The answer is between C and D
The question is will a negative value for n work? Suppose n = - 1 That means you go around the circle clockwise 1 time and though the question does not say it, you must start at the positive x axis.
Having said that 40 is plus.
The 360 starts at the + x axis. It doesn't matter how it got there. 40 degrees from the +x axis is in the first quadrant. It always will be.
D is correct but C is the better answer because it includes D.
We can use slope , point formula
y-y1=m(x-x1)
m is a slope=(y2-y1)/(x2-x1)=(-10-(-7))/(2-1)=-3
for example, we take the point (1, -7)
y-(-7)=-3(x-1)
y+7=-3x+3
y=-3x-4
Answer:
∠ SOU = 138°
Step-by-step explanation:
the opposite angles of a tangent kite are supplementary, sum to 180° , so
∠ SOU + ∠ STU = 180° , that is
∠ SOU + 42° = 180° ( subtract 42° from both sides )
∠ SOU = 138°
