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Agata [3.3K]
2 years ago
11

QUICKLY!! 10 POINTS BRAINLIEST FOR WHOVER ANSWERS CORRECTLY!!

Mathematics
2 answers:
AleksAgata [21]2 years ago
7 0

Answer:

2 \frac{1}{3} > 2 \frac{1}{6}

Step-by-step explanation:

\frac{5}{6}  < - \frac{1}{3}

This one is incorrect because a negative number can't be greater than a positive number.

--------------

2 \frac{1}{3} > 2 \frac{1}{6}

This one equals to:

2 \frac{2}{6} > 2 \frac{1}{6}

2 \frac{2}{6} is greater than 2 \frac{1}{6}. Therefore, this one is correct.

--------------

2 < - 2 \frac{1}{2}

Once again, a negative number can't be greater than a positive number. Hence, this is incorrect.

-------------

1 \frac{1}{4}  > 1 \frac{1}{3}

This one equals to:

1 \frac{3}{12}  > 1 \frac{4}{12}

1 \frac{3}{12} is not greater than 1 \frac{4}{12}. Hence, this one is incorrect.

Ugo [173]2 years ago
6 0

Answer:

The 2nd one

Step-by-step explanation:

2 1/3 are greater then 2 1/6

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Rewrite the following equation in standard form.<br><br> y= -2/7x + 5/8
nikitadnepr [17]
The equation in standard form would be,
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3 years ago
The intersection of 2 planes can be defined as a_____?
tamaranim1 [39]

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2 years ago
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3(x-2)+2(x+1)=-14<br> plz show work
Rom4ik [11]
Hello!

First, let's write the problem.
3\left(x-2\right)+2\left(x+1\right)=-14
Apply the distributive property on the left side of the equation.
=3x-6+2x+2
Add like terms.
=5x-4
Let's plug that in into the original equation.
5x-4=-14
Add 4 to both sides.
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Our final answer would be,
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You can feel free to let me know if you have any questions regarding this!
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Subtract the cube root of the product of h and 3k from the square of the sum of p and q​
ehidna [41]

Answer:

(p + q)²            -          ∛(h·3k)   or   (p + q)² - ∛(h·3k)  

Step-by-step explanation:

Cube root of x:  ∛x

Product of h and 3k:  h·3k

Sum of p and q:  p + q

*****************************

From (p + q)²      subtract ∛(h·3k)      This becomes, symbolically:

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Answer:

Sorry I could only find the answer to the second part.

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