Answer:
A. The distribution of sample means of the differences will be approximately normal if there are at least 30 years of data in the sample and/or if the population of differences in winning times for all years is normal.
Step-by-step explanation:
In other to perform a valid paired test, one of the conditions required is that, data for both groups must be approximately normal. To attain normality, the population distribution for the groups must be normal or based on the central limit theorem, the sample size must be large enough, usually n > 30. Hence, once either of the two conditions are met, the paired sample will be valid.
Answer:
(5,300)
Step-by-step explanation:
its the only one that its Y axis cant be divided by 5 and get a equal/even number
sorry I cant explain it well, but hope I somewhat helped ^^
Answer:
Only d) is false.
Step-by-step explanation:
Let
be the characteristic polynomial of B.
a) We use the rank-nullity theorem. First, note that 0 is an eigenvalue of algebraic multiplicity 1. The null space of B is equal to the eigenspace generated by 0. The dimension of this space is the geometric multiplicity of 0, which can't exceed the algebraic multiplicity. Then Nul(B)≤1. It can't happen that Nul(B)=0, because eigenspaces have positive dimension, therfore Nul(B)=1 and by the rank-nullity theorem, rank(B)=7-nul(B)=6 (B has size 7, see part e)
b) Remember that
. 0 is a root of p, so we have that
.
c) The matrix T must be a nxn matrix so that the product BTB is well defined. Therefore det(T) is defined and by part c) we have that det(BTB)=det(B)det(T)det(B)=0.
d) det(B)=0 by part c) so B is not invertible.
e) The degree of the characteristic polynomial p is equal to the size of the matrix B. Summing the multiplicities of each root, p has degree 7, therefore the size of B is n=7.
Answer:
ehhh- i give up
Step-by-step explanation:
Answer:
10 ring boxes
Step-by-step explanation:
First, we need to calculate the total surface area of each cube ring boxes
The surface area of each square boxes = 6L²
Given that L =1.5inches
Total surface area = 6(1.5)²
Total surface area = 6(2.25)
Total surface area = 13.5in²
<em>Since the question is incomplete. Let us assume the total surface area of the shipping box is 135in²</em>
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Number of ring boxes he can ship = 135/13.5
Number of ring boxes he can ship = 10
Hence the number of ring boxes he can ship is 10 ring boxes
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<u><em>NB: The total surface area of the shipping box was assumed</em></u>
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