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Answer:
The time taken for the upward motion is 1 second. The same time is taken for the downward motion
It reaches a maximum height of 4.9 meters.
Step-by-step explanation:
The equation of motion is:
Since the term which multiplies t squared is negative, the graph is concave down, that is, x increases until the vertex, where it reaches it's maximum height, then it decreases.
Vertex of a quadratic equation:
Quadratic equation in the format
The vertex is the point , in which
In this question:
So
Vertex:
The time taken for the upward motion is 1 second.
It reaches a maximum height of 4.9 meters.
Downward motion:
From the vertex to the ground.
The ground is t when x = 0. So
Or
It reaches the ground when t = 2 seconds.
The downward motion started at the vertex, when t = 1.
So the duration of the downward motion is 2 - 1 = 1 second.
Answer:
A
Step-by-step explanation:
Calculate the slope of the given points with the point (- 2, 5 )
If the slope is - then the point is on the line
Calculate slope m using the slope formula
m =
with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (6, - 1)
m = =
= -
← point (6, - 1) is on the line
Repeat with (x₁, y₁ ) = (- 2, 5 ) and (x₂, y₂ ) = (2, 8)
m = =
← point (2, 8) is not on the line
Repeat with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (- 5, 1)
m = =
=
← point (- 5, 1) is not on the line
Repeat with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (1, 1)
m = = -
← point (1, 1) is not on the line
Thus the point on the line is (6, - 1 ) → A