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3 years ago

What are the solutions to x^2-7x=-10

Mathematics

2 answers:

otez555 [7]3 years ago

5 0

Answer:

x= 5 and 2

Step-by-step explanation:

lesya [120]3 years ago

3 0

This should be the answer

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Name the angle in 4 ways.

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3 years ago

In an automobile parts factory, for every 175 carburetors 3 are found to be defective. At that rate how many carbureatots out of

Furkat [3]

Answer:

At the same rate 18 carburetors out of 1,050 could be expected to be detective.

Step-by-step explanation:

The number of carburetors tested = 175

Defective pieces out o f 175 = 3

So, ratio of defected to tested = 3 : 175

Now, the number of carburetors tested in second batch = 1,050

Here, let the defective pieces = m

So, by the Ratio of Proportion,

$\frac{3}{175} = \frac{m}{1050}$

or, $m = \frac{1050 \times 3}{175} = 18$

⇒ m = 18

Hence, at the same rate 18 carburetors out of 1,050 could be expected to be detective.

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3 years ago

At the city museum, child admission is $6.20 and adult admission is $9.90 . On Monday, three times as many adult tickets as chil

murzikaleks [220]

Can you please delete this. I have answered it wrong. Thanks

7 0

3 years ago

Also need help for this question!! Someone please help

SVEN [57.7K]

Given profit,
p(t)=0.4t^2+5.3t-8
After the first year, t=1
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7 0

3 years ago

Kesha threw her baton up in the air from the marching band platform during practice. The equation h(t) = −16t² + 54t + 40 gives

lapo4ka [179]

Answer:

a) 40 feet

b) 54 ft/min

c) 4 mins

Step-by-step explanation:

Solution:-

- Kesha models the height ( h ) of the baton from the ground level but thrown from a platform of height hi.

- The function h ( t ) is modeled to follow a quadratic - parabolic path mathematically expressed as:

h ( t ) = −16t² + 54t + 40

Which gives the height of the baton from ground at time t mins.

- The initial point is of the height of the platform which is at a height of ( hi ) from the ground level.

- So the initial condition is expressed by time = 0 mins, the height of the baton h ( t ) would be:

h ( 0 ) = hi = -16*(0)^2 + 54*0 + 40

h ( 0 ) = hi = 0 + 0 + 40 = 40 feet

Answer: The height of the platform hi is 40 feet.

- The speed ( v ) during the parabolic path of the baton also varies with time t.

- The function of speed ( v ) with respect to time ( t ) can be determined by taking the derivative of displacement of baton from ground with respect to time t mins.

v ( t ) = dh / dt

v ( t )= d ( −16t² + 54t + 40 ) / dt

v ( t )= -2*(16)*t + 54

v ( t )= -32t + 54

- The velocity with which Kesha threw the baton is represented by tim t = 0 mins.

Hence,

v ( 0 ) = vi = -32*( 0 ) + 54

v ( 0 ) = vi = 54 ft / min

Answer: Kesha threw te baton with an initial speed of vo = 54 ft/min

- The baton reaches is maximum height h_max and comes down when all the kinetic energy is converted to potential energy. The baton starts to come down and cross the platform height hi = 40 feet and hits the ground.

- The height of the ball at ground is zero. Hence,

h ( t ) = 0

0 = −16t² + 54t + 40

0 = -8t^2 + 27t + 20

- Use the quadratic formula to solve the quadratic equation:

$t = \frac{27+/-\sqrt{27^2 - 4*8*(-20)} }{2*8}\\\\t = \frac{27+/-\sqrt{1369} }{16}\\\\t = \frac{27+/-37 }{16}\\\\t = \frac{27 + 37}{16} \\\\t = 4$

Answer: The time taken for the baton to hit the ground is t = 4 mins

3 0

3 years ago