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Kobotan [32]
2 years ago
11

(If A+B+C=180) tan 2A + tan 2B + tan 2C = tan 2A tan 2B tan 2C​

Mathematics
1 answer:
zavuch27 [327]2 years ago
7 0

Step-by-step explanation:

Hey there!

See explanation in picture.

<em><u>Hope </u></em><em><u>it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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Emery bought 3 cans of beans that had a total weight of 2.4 pounds. If each can of beans weighed the same amount, which model co
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Answer:

  • y=0.8x
  • See Explanation for others

Step-by-step explanation:

The 3 cans of beans had a total weight of 2.4 Pounds

Therefore:

  • 1 can of beans = (2.4 ÷ 3) =0.8 Pounds

The following applies from the options.

  • y=0.8x where y is the weight and x is the number of cans.
  • A 2-column table with 3 rows. Column 1 is labeled number of cans with entries 5, 15, 20. Column 2 is labeled total weight (in pounds) with entries 4, 12, 16.

Using y=0.8x

When x=5, y=0.8 X 5=4

When x=15, y=0.8 X 15=12

When x=20, y=0.8 X 20=16

\left|\begin{array}{c|c}\text{Number of Cans,x}&\text{Total Weight (in Pounds),y}\\-------&--------\\5&4\\15&12\\20&16\end{array}\right|

  • On a coordinate plane, the x-axis is labeled number of cans and the y-axis is labeled total weight (in pounds. A line goes through points (5, 4) and (15, 12). This can be clearly seen from the table above as (5,4) and (15,12) are points on the line.
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At a lunch stand, each hamburger has 50 more calories than each order of fries. If 2 hamburgers and 3 orders of fries have a tot
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Answer: 960 calories

Step-by-step explanation:

Given

Each hamburger has 50 more calories than each order of fries

Suppose each order of fries has x calories

so, hamburger has x+50 calories

There are total of 1700 calories available. Thus, we can write

\Rightarrow 2(x+50)+3x=1700\\\Rightarrow 2x+3x=1700-100\\\Rightarrow 5x=1600\\\Rightarrow x=320

So, each order of fries has 320 calories

For 3 orders, it is 320\times 3=960 calories

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