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3 years ago

Need help with 15, 16, 17 and 18. Please provide an explanation. Also list in least to greatest. Thank you in advance!

Mathematics

1 answer:

EleoNora [17]3 years ago

8 0

15. 99%, 0.95, 5/9, 9.5%
Make all decimals: .99, .95, .55, .095
List: Zero is less than 9 or 5 so it's first than 5 and than 9, you have two 9's so 5 is less than 9: .095, .55, .95, .99

16. 3/8, 50%, 0.35, 38%
Same steps: .375, .50, .35, .38
3 is less than 5 and 5 is less than 8 or 7 so: .35, .375, .38, .5

And do the same thing for the other two problems :)

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3 years ago

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Answer:

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3 years ago

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MArishka [77]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

A carrot has 55 grams of sugar per serving. A banana has 15 grams of sugar per serving. Which statement is true?

GREYUIT [131]

For an equal number of servings, the bananas will have three times as much sugar.

To put it in perspective:
When we have one serving of each fruit, the carrot will give you 5 grams of sugar whereas banana will give you 15 grams.

Hope this helps!

7 0

3 years ago

A true/false test has 40 questions. Suppose a passing grade is 30 or more correct answers. Test the claim that a student knows m

Angelina_Jolie [31]

Answer:

z≈3.16

p≈0.001

we reject the null hypothesis and conclude that the student knows more than half of the answers and is not just guessing in 0.05 significance level.

Step-by-step explanation:

As a result of step 2, we can assume normal distribution for the null hypothesis

z statistic is computed as follows:

z= $\frac{X-M}{\frac{\sqrt{p*(1-p)} }{\sqrt{N} } }$ where

X is the proportion of correct answers in the test ( $\frac{30}{40}$ )
M is the expected proportion of correct answers according to the null hypothesis (0.5)

p is the probability of correct answer (0.5)
N is the total number of questions in the test (40)

z= $\frac{0.75-0.50}{\frac{\sqrt{0.5*(0.5)} }{\sqrt{40} } }$ ≈ 3.16

And corresponding p value for the z-statistic is p≈0.001.

Since p<0.05, we reject the null hypothesis and conclude that the student knows more than half of the answers and is not just guessing in 0.05 significance level.

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3 years ago