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babymother [125]
2 years ago
13

Help me now this is so hard​

Mathematics
2 answers:
Kay [80]2 years ago
6 0

Answer:

what is the question?

Step-by-step explanation:

uhh ok

True [87]2 years ago
6 0

Answer:Do you have a picture of the question?

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Question: Consider the domain (D) and rule of each function. Determine the range of the function. 1. D = {0, 1, 2, 3}; f(x) = 3x
Maksim231197 [3]

For every function you need evaluate the function for every value in the domain D. And the collection of this values correspond to the range of the function.

1. D = \{0,1,2,3 \}, R = \{f(0), f(1), f(2), f(3) \} = \{-5, -2, 1, 4 \}.

2. D = \{-1,0,1 \}; R= \{f(-1), f(0), f(1)\} = \{0, 1, 0 \} = \{0,1\}

3. D = \{-2,-1,0,1 \}; R = \{f(-2), f(-1), f(0), f(1) \} = \{0, -2, -2, 0 \} = \{-2,0\}

4. D = \{0,1,2,3 \}; R =\{f(0), f(1), f(2), f(3) \} = \{3, 1, -1, -3 \}

5 0
3 years ago
A number has the same digit inits hundreds place and its hundredths place. how many times greater is the value of the digit in t
lorasvet [3.4K]

Answer:100

Step-by-step explanation: i looked it up

3 0
3 years ago
Which is more precise 5 kg or 5212 g
Dahasolnce [82]
5 kg is more precise because if you said 5212 g, they will be trying to see what the precise answer is so if you say 5 kg that will save all of the work. 

P.S.: its not 5212 g, its 5000 g. :)
4 0
3 years ago
PLEASE HELP ME ALL 3 THIS QUESTION! (you just need to check my answer is right or wrong)
inna [77]

Answer:

1 and 3 is right and I’m pretty sure 2 is right also.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
The areas of two similar triangles are 72dm2 and 50dm2. The sum of their perimeters is 226dm. What is the perimeter of each of t
astraxan [27]

Answer:

Hence, the perimeter of the triangles are:

P=123.2727 dm

P'=102.7272 dm

Step-by-step explanation:

In two similar triangles:

The ratio of the areas of two triangle is equal to the square of their perimeters.

Let A and A' represents the area of two triangles and P and P' represents their perimeter.

Then they are related as:

\dfrac{A}{A'}=\dfrac{P^2}{P'^2}

We are given:

A=72 dm^2  , A'=50 dm^2

and P+P'=226 dm.-----------(1)

i.e. \dfrac{72}{50}=\dfrac{P^2}{P'^2}\\\\\dfrac{36}{25}=\dfrac{P^2}{P'^2}

on taking square root on both the side we get:

\dfrac{P}{P'}=\dfrac{6}{5}\\\\P=\dfrac{6}{5}P'

Now putting the value of P in equation (1) we obtain:

\dfrac{6}{5}P'+P'=226\\\\\dfrac{6P'+5\times P'}{5}=226\\\\\dfrac{6P'+5P'}{5}=226\\\\11P'=226\times 5\\\\11P'=1130\\\\P'=\dfrac{1130}{11}=102.7272

Hence,

P=226-102.7272=123.2727

Hence, the perimeter of the triangles are:

P=123.2727 dm

P'=102.7272 dm

6 0
3 years ago
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