Answer:
1
Step-by-step explanation:
Using the trigonometric identities
tan(90 - x) = cotx , cotx =
Given
tan1tan2tan3....................... tan87tan88tan89
= tan1tan2tan3............... tan(90-3)tan(90-2)(tan90 - 1)
= tan1tan2tan3.............. cot3cot2cot1
= tan1cot1tan2cot2tan3cot3 ........................
= 1 × 1 × 1 ×....................... × 1
= 1
Answer:
Equation of other line passing through point (6 , - 11) and parallel to given line is y = - 23 x + 127 .
Step-by-step explanation:
Given as :
The equation of one line
y = - 23 x + 12
∵ The equation of line in slope-intercept form is
y = m x + c
where m is the slope of line and c is y-intercept
Now, Compare given line with standard line equation
So, The slope of given line = m = - 23
Now, Again
Other line is passing through point (6 , - 11) and is parallel to given line
so, both the lines are parallel
For parallel line condition , Slope of both lines are equal
Let The slope of other line = M
So, M = m = - 23
Now, Equation of other line passing through point (6 , - 11) and slope - 23 in slope-point form
y - = M × (x -
)
i.e y - ( - 11) = (- 23) × (x - 6)
Or, y + 11 = - 23 × x + 138
Or, y = - 23 x + 138- 11
i.e y = - 23 x + 127
So, The equation of other line y = - 23 x + 127
Hence, Equation of other line passing through point (6 , - 11) and parallel to given line is y = - 23 x + 127 . Answer