Answer: <em>She earned $72 per day. </em>
<em>The computation that will give Samantha's daily pay is: 
</em>
Step-by-step explanation:
Samantha did not work on weekends. That means, <u>she worked for 5 days in a week</u>.
Given that, she worked at the insurance company for 11 weeks. So, <u>the total number of her working days</u> 
She earned a total of $3,960.
So, the amount she earned daily 
Exponential growth/decay rule with general function is:<span>y=y(0)<span>e<span>kt</span></span></span>
with k is growth/decay constant rate.
(1) Deer population function
y(0) = 1253
k
= 3%
t
= 6 (years)
y(6) = 1253 . e^(0.03*6) ~ 1500 (deers)
: 1496 deers
(2) Growth factor b is rate 9.5% = 0.095
Answer:
Chisquare statistic
Step-by-step explanation:
The most appropriate test to use here is the Chisquare test as it isemployed when testing the relationship between two variables. Both the T statistic and z statistics are the used for testing difference in means. However, in the analysis above, we are given two variables with each having its own levels. Hence, the Chisquare test is the most appropriate in this kind of situation a it measures if a difference exists between the two variables. It tests if they are related or independent of on one another
Answer:
The prices at which manager predict that at least 55 hats will be sold would be would be of $38
Step-by-step explanation:
According to the given data we the following:
Number of hats sold at $18=115
The manager predicts at 3 less will sold for every rise in 1 $ for at least 55 hats.
Therefore, reduction in number=115 hats-55 hats=60
So, increase in price=reduction in number/number of hats manager predicts that will be sold for every $1 increase in price
increase in price=60/3=$20
Therefore, prices at which manager predict that at least 55 hats will be sold would be=$18+$20=$38
The prices at which manager predict that at least 55 hats will be sold would be would be of $38
Answer:
im sorry if not but i think its 7.24
Step-by-step explanation:
