Answer:
4c^2+7c-5=0
4c^2+7c=5
4c^2+7c=5
4c^2+7c-5=0\quad :\quad c=\frac{-7+\sqrt{129}}{8},\:c=\frac{-7-\sqrt{129}}{8}\quad \left(\mathrm{Decimal}:\quad c=0.54472\dots ,\:c=-2.29472\dots \right)
Hope This Helps!!!
<em>Rearrange unknown terms to the left side of the equation</em>
![\boldsymbol{\sf{ 9x > 50.4-9 \ \ \longmapsto \ \ \ [Subtract]}}](https://tex.z-dn.net/?f=%5Cboldsymbol%7B%5Csf%7B%20%209x%20%3E%2050.4-9%20%5C%20%5C%20%5Clongmapsto%20%5C%20%5C%20%5C%20%5BSubtract%5D%7D%7D)
<em>Calculate the sum or difference.</em>

<em>Convert decimal to fraction.</em>

<em>Reduce the greatest common factor for both sides of the inequality.</em>
<em> </em>
<em>Reduce the fraction</em>

Answer:
71
Step-by-step explanation:
This arithmetic sequence starts at 1 and increases by 5 every time. The formula for this sequence could be expressed as A(n) = 1 + 5(n-1).
Since you're finding the 15th term, substitute n = 15 into the formula.
A(15) = 1 + 5((15)-1) = 1 + 5(14) = 1 + 70 = 71