Answer:
The minor arc HK is 60 degrees
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
The inscribed angle is half that of the arc it comprises.
so

we have

substitute the given value


Remember that the measure of the minor arc must be less than 180 degrees
therefore
The minor arc HK is 60 degrees
To find the x-intercept, you need to set y equal to zero(think about this on a graph!)
This will become:
x + 2(0) = 8
If we remove the unnecessary zero:
x = 8
That's the x intercept, which can be expressed as the point (8,0).
To find the y-intercept, you need to set x equal to zero(again, think about that on a graph!)
This becomes:
0 + 2y = 8
Remove the unnecessary 0:
2y = 8
Divide both sides by 2:
y = 4
There ya go! Or, in point form: (0, 4)
Hope this helped! :)
~Chrys
The first quartile of the data set is 28 because it is the median of the lower set.