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marissa [1.9K]
3 years ago
11

How do I write 3x-1<_8 on a number line

Mathematics
1 answer:
Usimov [2.4K]3 years ago
8 0
Solid circle over 3 line going left 
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2^3a^7 times 2a^3 NEEE HELP​
hichkok12 [17]

Step-by-step explanation:

explain step by step on photo, double check just in case

6 0
3 years ago
What is the factored form of 6n4 – 24n3 + 18n?
seropon [69]

Answer: Its factored form will be

6n(n-1)(n^2-3n-3)

Step-by-step explanation:

Since we have given that

6n^4-24n^3+18n

So, we need to factor ,

6n(n^3-4n^2+3)

Now,

\text{Let }p(n)=n^3-4n^2+3

Now, by hit and trial method, we put n=1,

p(1)=1^3-4\times1^2+3=1-4+3=1-1=0

n=1\\n-1=0

So, n-1 is also factor of p(n).

Now,

\frac{n^3-4n^2+3}{n-1}=n^2-3n-3

So, its factored form will be

6n(n-1)(n^2-3n-3)

8 0
3 years ago
Read 2 more answers
Cual es la relacion entre &lt;a y &lt;b?
RideAnS [48]

Answer:

Angulos suplementarios

7 0
2 years ago
Write an equation of the hyperbola given that the center is at (2, -3), the vertices are at (2, 3) and (2, - 9), and the foci ar
zavuch27 [327]
Check the picture below.

so, the hyperbola looks like so, clearly a = 6 from the traverse axis, and the "c" distance from the center to a focus has to be from -3±c, as aforementioned above, the tell-tale is that part, therefore, we can see that c = 2√(10).

because the hyperbola opens vertically, the fraction with the positive sign will be the one with the "y" in it, like you see it in the picture, so without further adieu,

\bf \textit{hyperbolas, vertical traverse axis }&#10;\\\\&#10;\cfrac{(y- k)^2}{ a^2}-\cfrac{(x- h)^2}{ b^2}=1&#10;\qquad &#10;\begin{cases}&#10;center\ ( h, k)\\&#10;vertices\ ( h,  k\pm a)\\&#10;c=\textit{distance from}\\&#10;\qquad \textit{center to foci}\\&#10;\qquad \sqrt{ a ^2 + b ^2}\\&#10;asymptotes\quad  y= k\pm \cfrac{a}{b}(x- h)&#10;\end{cases}\\\\&#10;-------------------------------

\bf \begin{cases}&#10;h=2\\&#10;k=-3\\&#10;a=6\\&#10;c=2\sqrt{10}&#10;\end{cases}\implies \cfrac{[y- (-3)]^2}{ 6^2}-\cfrac{(x- 2)^2}{ b^2}=1&#10;\\\\\\&#10;\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ b^2}=1&#10;\\\\\\&#10;c^2=a^2+b^2\implies (2\sqrt{10})^2=6^2+b^2\implies 2^2(\sqrt{10})^2=36+b^2&#10;\\\\\\&#10;4(10)=36+b^2\implies 40=36+b^2\implies 4=b^2&#10;\\\\\\&#10;\sqrt{4}=b\implies 2=b\\\\&#10;-------------------------------\\\\&#10;\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 2^2}=1\implies \cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 4}=1

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2 years ago
Analyze the following situations that represent a relationship between x and y. Which situations can be modeled by the equation
SCORPION-xisa [38]

Answer:

I think it's A and D

Step-by-step explanation:

For option A, y would be the height or total growth, and x would be time or months and total height = 0.23 feet × 7.5 months

for option D, y would be the total amount of money spent and x would be the number of granola bars bought.  total money spent = $0.23 × number of granola bars bought

Options B and C don't work because we don't know the initial values and an initial value would be represented in the equation.

In option E, 0.23 represents the total growth in 7 days, so it would be the total instead of the rate of change

8 0
3 years ago
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