The thing about that problem is that when the circle is inscribed inside that triangle, the side measures created are doubled. By that I mean that the 9 on the top right is also the measure of the top left. Same thing for the 13 and the 16. The lower left unmarked side length is 13, the lower right side length is 16. Now add it all up: 9+9+13+13+16+16
The height is 24.
We can use Pythagorean’s Theorem: a^2+b^2=c^2
substituting values we get:
a^2+7^2=25^2
Solving we get:
a^2+49=625
a^2=576
a=24.
So the height is 24.
Hope this helps!
The numbers are 5 and 12.
Smaller number = x
Larger number = y
x +y =17
y = 3x - 3
x +3x -3 = 17
4x = 20
x = 5
smaller number is 5
y = 3(5) - 3
y = 12
larger number is 12.
There are 98 terms.
98*(33+130)/2 = 7987
13 x 6 = 78 it cant be multiplied anymore so it can go into 80 about 6 times.
