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Dominik [7]
3 years ago
7

Which statements are true

Mathematics
2 answers:
Dominik [7]3 years ago
6 0
The first, third, and sixth are correct.
Flura [38]3 years ago
6 0
AB and CG are parallel
CG and RS are perpendicular
AB and RS must intersect
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15. Suppose a box of 30 light bulbs contains 4 defective ones. If 5 bulbs are to be removed out of the box.
Naddika [18.5K]

Answer:

1) Probability that all five are good = 0.46

2) P(at most 2 defective) = 0.99

3) Pr(at least 1 defective) = 0.54

Step-by-step explanation:

The total number of bulbs = 30

Number of defective bulbs = 4

Number of good bulbs = 30 - 4 = 26

Number of ways of selecting 5 bulbs from 30 bulbs = 30C5 = \frac{30 !}{(30-5)!5!} \\

30C5 = 142506 ways

Number of ways of selecting 5 good bulbs  from 26 bulbs = 26C5 = \frac{26 !}{(26-5)!5!} \\

26C5 = 65780 ways

Probability that all five are good = 65780/142506

Probability that all five are good = 0.46

2) probability that at most two bulbs are defective = Pr(no defective) + Pr(1 defective) + Pr(2 defective)

Pr(no defective) has been calculated above = 0.46

Pr(1 defective) = \frac{26C4  * 4C1}{30C5}

Pr(1 defective) = (14950*4)/142506

Pr(1 defective) =0.42

Pr(2 defective) =  \frac{26C3  * 4C2}{30C5}

Pr(2 defective) = (2600 *6)/142506

Pr(2 defective) = 0.11

P(at most 2 defective) = 0.46 + 0.42 + 0.11

P(at most 2 defective) = 0.99

3) Probability that at least one bulb is defective = Pr(1 defective) +  Pr(2 defective) +  Pr(3 defective) +  Pr(4 defective)

Pr(1 defective) =0.42

Pr(2 defective) = 0.11

Pr(3 defective) =  \frac{26C2  * 4C3}{30C5}

Pr(3 defective) = 0.009

Pr(4 defective) =  \frac{26C1  * 4C4}{30C5}

Pr(4 defective) = 0.00018

Pr(at least 1 defective) = 0.42 + 0.11 + 0.009 + 0.00018

Pr(at least 1 defective) = 0.54

3 0
3 years ago
If you know that the exact volume of a cylinder is 500 π cm3, how can you find the approximate volume, without knowing the heigh
grandymaker [24]

Answer:

The approximate volume is 1,570\ cm^{3}

Step-by-step explanation:

we know that

The exact volume of the cylinder is  

V=500\pi \ cm^{3}

so

To find the approximate volume of the cylinder, substitute the term \pi by the approximate value of  3.14 and then multiply  

so

V=500(3.14)=1,570\ cm^{3}

6 0
3 years ago
Statements that can be proven by a logical sequence of statements is called a(n)
laila [671]
A)Theorem. every theorem can be proved.
6 0
3 years ago
Read 2 more answers
Write in standard notation. 6.9 × 10^-3
Dafna1 [17]

0.0069

Step-by-step explanation:

6.9 move the decimal 3 places to the left

8 0
3 years ago
A garden is designed in the shape of a rhombus formed from 4 identical 30°-60°-90° triangles. The shorter distance across the mi
Alchen [17]
        It also means that a rhombus is formed from 2 identical equilateral triangles ( 2 identical 30 - 60 - 90 triangles forms one equilateral ) and a side of that triangle measures : 30 feet. 
      Answer:
      The perimeter of the garden :  4 * 30 = 120 feet
4 0
3 years ago
Read 2 more answers
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