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lapo4ka [179]
3 years ago
12

Finding an irrational number between which given pair of numbers supports the idea that irrational numbers are dense in real num

bers? 3.14 and pi 3.33 and 1/3 e squared and square root of 5 square root of 64 over 2 and square root of 16
Mathematics
1 answer:
snow_lady [41]3 years ago
6 0

Answer:

So, we need to find irrational numbers between the given pairs.

Remember that the sum between an irrational number and an rational number is irrational.

For example, for the first case, we want a irrational number between:

3.14 and pi:

pi = 3.14159265.... is irrational

pi - 0.0001 = 3.14159265... - 0.0001 = 3.14149265...

So this number:

3.14149265...

is an irrational number larger than 3.14 and smaller than pi.

Second cacse:

3.33 and 1/3

(here the range would be actually:

1/3 = 0.33 and 3.33

So we want an irrational number larger tan 0.33 and smaller than 3.33

here we can just use pi = 3.141592...

third case:

e^2 and √5

Firs let's write these numbers so we can see how they look.

e^2  =7.389...

√5 = 2.236

So we want a number larger than 2.236... and smaller than 7.389...

Again, here we can use pi = 3.141592...

2.236... < 3.141592... < 7.389...

final case:

√(64/2) and √16

we have:

√(64/2) = 5.65

√16 = 4

So we want an irrational number larger than 4 and smaller than 5.65

Again, let's use our beloved number pi.

we have that:

pi + 1  is an irrational number:

pi + 1 = 3.14159265... + 1.0 = 4.14159265....

This number, 4.14159265..., is irrational, is larger than 4 and is smaller than 5.65, so we found the irrational number between the given pair of numbers.

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Answer:

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Step-by-step explanation:

Hello!

A semicircle's perimeter can be found using the formula: P = \pi r + 2r

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