Let the weight of the full Volume of nails in the box be W.
Let the weight of the box be B.
2/3 W + B = 130 ........i From the first statement.
3/8 W + B = 74 ......ii From the second statement.
Equation (i) Minus (ii)
2/3 W - 3/8 W + B - B = 130 - 74
(16W - 9W) / 24 = 56
7W / 24 = 56.
W = 56 * 24 / 7
W = 192 Pounds.
Substituting V = 64 in equation (i)
2/3 W + B = 130
2/3 * 192 + B = 130
2 * 64 + B = 130
128 + B = 130
B = 130 -128 = 2.
Therefore, weight of box, B = 2 pounds.
Answer: the following are required for IV-3 to have condition
Explanation:
-II-4 passes an X b chromosome to III-4 (probability = 1/2).
-If III-4 has the genotype X B X b (accounted for by the above probability), then she passes an X b chromosome to IV-3 (probability = 1/2).
-III-5 passes a Y chromosome to IV-3 (probability = 1/2).
All of these requirements are needed in sequence, so you apply the product rule here, too (1/2 x 1/2 x 1/2 = 1/8).
Once the individual probabilities are known, the sum and/or product rules can be used for various combinations (both conditions, either condition, etc.).
Since it is the midpoint we can say:
12x - 1 = 8x +11
All we have do to is get all the x's alone on one side
12x - 1 = 8x + 11
12x = 8x + 12 (add both sides by 1)
4x = 12 (subtract both sides by 8x)
x = 3 (divide both sides to get what x is)
Answer is 64 and a factor is 6/4 .
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