Y-INTERCEPT

The y-intercept is where the equation/curve/parabola cosses the y-axis.
The y-axis is where x = 0. (The x-axis is where y = 0)
To find the y-intercept:

The y-intercept must be at (0, 10)
X-INTERCEPT (ROOTS/SOLUTIONS)

We need to use the quadratic formula
The quadratic formula helps us find what values of
make the equation = 0
Quadratic formula: 

The x-intercepts are at:

Answer:
It's 10
Step-by-step explanation:
10 can be divided by five and 5 can also be divided by five and it's the least number that can be divided by five.
<span>The length of an arc, L = theta/360 * 2 * pie * r
Where theta = 81 and r = 10ft = 3.048m
So length = 81/360 * 2 * pie * 3.048
L = * 0.225 * 2 * pie * 3.048
L = 1.37 * pie
L = pie. Option A</span>
Answer:
First option: cos(θ + φ) = -117/125
Step-by-step explanation:
Recall that cos(θ + φ) = cos(θ)cos(φ) - sin(θ)sin(φ)
If sin(θ) = -3/5 in Quadrant III, then cos(θ) = -4/5.
Since tan(φ) = sin(φ)/cos(φ), then sin(φ) = -7/25 and cos(φ) = 24/25 in Quadrant II.
Therefore:
cos(θ + φ) = cos(θ)cos(φ) - sin(θ)sin(φ)
cos(θ + φ) = (-4/5)(24/25) - (-3/5)(-7/25)
cos(θ + φ) = (-96/125) - (21/125)
cos(θ + φ) = -96/125 - 21/125
cos(θ + φ) = -117/125
Answer:
=5
Step-by-step explanation:
(5)=-7/2(-2)-7
5=7-7
=5