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marissa [1.9K]
3 years ago
10

Linda is meeting Steve. Linda walks at 2.5 miles per hour. Steve is walking at 1.5 miles per hour. They are 5 miles apart. How l

ong will it take for them to meet?
Mathematics
2 answers:
V125BC [204]3 years ago
5 0

Step-by-step explanation:

First add.2 subtract.3 thats youre answer i think

ivanzaharov [21]3 years ago
5 0

Answer: it will take 1.25 hours before they meet

Step-by-step explanation:

Linda is meeting Steve. Linda walks at 2.5 miles per hour.

Distance = speed × time

time = distance / speed

Let t represent the time it takes Linda to cover her distance.

Distance covered by Linda = 25×t = 2.5t miles

Steve is walking at 1.5 miles per hour.

Let t1 represent the time it takes Steve to cover his distance.

Distance covered by Steve = 1.5×t = 1.5 t1 miles.

They are 5 miles apart. It means that by the time they met, they have covered a 5 miles. Therefore

2.5t + 1.5t1 = 5

Assuming both of them spent the same time walking, it means that

t = t1

2.5t + 1.5t = 5

4t = 5

t = 5/4 = 1.25 hours

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Elimination Method

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\begin{gathered} -2X+Y-2Z=-8 \\ 7X+Y+Z=-1 \\ -5X-2Y+Z=9 \end{gathered}

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