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Morgarella [4.7K]
3 years ago
9

Explain how to graph the following function and determine its domain and range y=-x^2+4-7 ​

Mathematics
1 answer:
Bad White [126]3 years ago
3 0

Answer:

Domain is: ( − ∞ , ∞ ) ,  { x | x ∈ R }

range is: ( − ∞ , − 3 ]  ,  { y | y ≤ − 3 }

Graph the parabola using the direction, vertex, focus, and axis of symmetry.

Step-by-step explanation:

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3 years ago
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If g(x)= x^2-2x-6 and h(x)= 2x^2-5x+2 find (h-g) (-2)
Natalka [10]

Answer:

<h2>(h - g)( - 2) = 18</h2>

Step-by-step explanation:

g(x) = x² - 2x - 6

h(x) = 2x² - 5x + 2

To find (h-g) (-2) we must first find h - g(x)

To find h - g(x) subtract g(x) from h(x)

We have

<h3>(h - g)(x) =  {2x}^{2}  - 5x + 2 - ( {x}^{2}  - 2x - 6)  \\  =  {2x}^{2}  - 5x + 2 -  {x}^{2}  + 2x + 6 \\  =  {2x}^{2}  -  {x}^{2}  - 5x + 2x + 2 + 6</h3><h3>(h - g)(x) =  {x}^{2}  - 3x + 8</h3>

To find (h-g) (-2) substitute the value of x that's - 2 into (h - g)(x) that's replace every x in (h - g)(x) by - 2

That's

<h3>(h - g)( - 2) =  ({ - 2})^{2}  - 3( - 2) + 8 \\  = 4 + 6 + 8 \\  = 10 + 8</h3>

We have the final answer as

<h3>(h - g)( - 2) = 18</h3>

Hope this helps you

7 0
3 years ago
Find the volume of the largest rectangular box in the first octant with three faces in the coordinate planes and one vertex in t
makkiz [27]

Answer:

Step-by-step explanation:

x + 2y + 3z = 12

z=\frac{12-x-2y}{3}

Volume = V=f(x,y) = xy(\frac{12-x-2y}{3} )

find partial derivatives using product rule

f_x =\frac{y}{3} (12-2x-2y)\\f_y = \frac{x}{3} (12-x-4y)

i.e.

Using maximum for partial derivatives, we equate first partial derivative to 0.

y=0 or x+y =6

x=0 or x+4y =12

Simplify to get y =2, x = 4

thus critical points are (4,2) (6,0) (0,3)

Of these D the II derivative test gives

D<0 only for (4,2)

Hence maximum volume is when x=4, y=2, z= 4/3

Max volume is = 4(2)(4/3) = 32/3

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3 years ago
This app doesn’t know how to read a picture
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It’s the 3rd one hopefully this helps
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3 years ago
Function g is defined below.
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Rule: if you have graph of function y=f(x) and a>0, then:
1. y=f(x-a) is translation a units right;
2. y=f(x+a) is translation a units left;
3. y=f(x)-a is translation a units down;
4. y=f(x)+a is translation a units up;

Since g(x)=f(x+2)-5, then firstly you have to translate the graph of function y=f(x) two units left and secondly 5 units down.


6 0
3 years ago
Read 2 more answers
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