Pretty sure its y > -6.2
This is because you subtract 4 from both sides and get y > -6.2
Please correct me if im wrong thx!
Answer:
You must survey 784 air passengers.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
The margin of error is:
95% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
Assume that nothing is known about the percentage of passengers who prefer aisle seats.
This means that 
, which is when the largest sample size will be needed.
Within 3.5 percentage points of the true population percentage.
We have to find n for which M = 0.035. So
You must survey 784 air passengers.
Honestly I don’t know the answer
<span>Given:
xbar = 20 min
standard deviation = 8 min
total sample = 240
Required:
how many gym members are expected to spend 4 min and 36 min on a treadmill today
Solution:
sd</span>² = (∑(x - xbar)²) / N - 1
there are 42 gym members at 4 minutes and 200 gym members in 36 minutes.
The factor outside the parentheses is -1. Distribute using that factor.
2 - (4 - <em>x</em>) = 7<em>x</em> - 5<em>x</em>
<em />
-1 * 4 = -4 and -1 * -<em>x</em> = <em>x</em>
<em />
2 - 4 + <em>x</em> = 7<em>x</em> - 5<em>x</em>
Simplify.
-2 + <em>x</em> = 2<em>x</em>
<em>x</em> = 2<em>x</em> + 2
-<em>x</em> = 2
<em>x</em> = -2
<h3>
Answer:</h3>
<em>x</em> = -2
