Answer:
Yes, we can conclude that the population standard deviation of TV watching times for teenagers is less than 2.66
Step-by-step explanation:
H0 : σ² = 2.66²
H1 : σ² < 2.66²
X²c = (n - 1)*s² ÷ σ²
sample size, n = 40
Sample standard deviation, s = 1.9
X²c = ((40 - 1) * 1.9²) ÷ 2.66²
X²c = 140.79 ÷ 7.0756
X²c = 19.897
Using a confidence level of 95%
Degree of freedom, df = n - 1 ; df = 40 - 1 = 39
The critical value using the chi distribution table is 25.6954
Comparing the test statistic with the critical value :
19.897 < 25.6954
Test statistic < Critical value ; Reject the Null
Hence, we can conclude that the population standard deviation of TV watching times for teenagers is less than 2.66
Answer:
should be 1007
1007.2932714 if we're being exact.
It seems that you have missed the necessary options for us to answer this question, but anyway, here is the answer. Based on the given scenario above about what Annabelle did, the kind of statistical investigation that she performed was a SURVEY. Hope this helps.
(3 + 5i)(4 + 4i)=12 + 12i + 20i -20
The answer is: -8 + 32i
Answer:
a^6/(b^12c^3d)
Step-by-step explanation:
