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3 years ago

What is the gcf and lcm of 12,42

Mathematics

1 answer:

nika2105 [10]3 years ago

3 0

The gcf is 6.

The lcm is 84.

HOPE THIS HELPED :)

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17% of students in a class have brown hair. If 6 students are chosen at random, what is the probability that exactly 3 have brow

dezoksy [38]

Answer:

6.8%

Step-by-step explanation:

the question has no information about class size (no. of student in class)

assume no. of student is infinite

P(3brown out of 6) = 6C3 * P(brown)^3 * P(not brown)^3

= 20 * 0.004913 * 0.695789

= 0.06837

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2 years ago

John went to dave and busters each game cost $3 what is the rate of change?

Darya [45]

The rate of change is 3 because each game costs $3 and the y-value will go up by 3 when the x-value goes up by 1. Hope this helps!

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3 years ago

What is the midpoint of AB?

spayn [35]

Answer: Point G.

Step-by-step explanation:

Count the number of spaces between points A and B. Then divide that number by 2 and count that many spaces from one point.

14/2=7

I hope this helps!! Pls mark brainliest :)

6 0

2 years ago

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Someone help me ASAP 10 points each

tia_tia [17]

Answer:

Step-by-step explanation:

4 0

3 years ago

Suppose the lengths of two sides of a right triangle are represented by 2x and 3 (x + 1), and the longest side is 17 units. Find

densk [106]

Answer:

x=4

Step-by-step explanation:

Step 1:-

given the lengths of two sides of a right angle are represented by 2x and 3(x+1) and longest side is 17 units.

AB = 2x and BC = 3(x+1) and longest side AC= 17

by using Pythagoras theorem

$AC^2 = AB^2 + BC^2$

step 2:-

The hypotenuse is longest side is AC = 17 units

(17)^2 = 4x^2 +9(X+1)^2

on simplification, we will use formula

$(a + b)^2 = a^2 +2ab+b^2$

289 = 4x^2 +9(x^2+2x+1)

$13x^2 +18x-280 = 0$

finding factors 70 X 52 = 3640

$13x^2 +70x-52x-280 = 0$

$13x^2 -52x+ 70x-280 = 0$

Taking common , we get

13x(x-4)+70(x-4)=0

x-4=0 and 13x+70=0

x=4 and $13x =-70$

x=4 and $x=\frac{-70}{13}$

we can not choose negative value so x value is 4

Final answer:- x = 4

verification:-

$AC^2 = AB^2 + BC^2$

289 = 4(4)^2+9(4+1)^2

289 = 64 +9(25)

289=289

6 0

4 years ago

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