78 (1 + 2 + 3 . . + 12) so 78/3 = 26 and 11 + 12 + 1 + 2
10 + 9 + 3 + 4
8 + 7 + 6 + 5
that means you will draw one line below the 11 and across to below the 2 and the second line would be above the 8 and across to below the 4.
Seeing is believing . . .draw and label a clock face then add the two lines!
Answer:
(3,6)
Step-by-step explanation:
Collect like terms
y -5x = -9
y + 2x = 12
Using elimination method
Subtract equation 2 from equation 1
y - 5x = -9
y + 2x = 12
---------------
0. -7x = -21
Divide both sides by -7
-7x = -21
---- -----
-7 -7
x = 3
Substitute x=3 into equation 1
y = 5(3) - 9
y = 15 - 9
y = 6
Solution is (x,y) = (3,6)
A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola y = 7 − x 2 y=7-x2. what are the dimensions of such a rectangle with the greatest possible area?
Answer:
c) 50.7
d) 206.3
Step-by-step explanation:
c) 50 + 0.7 = 50.7
d) 200 + 6 + 0.3 = 206.3
Answer:
table one
Step-by-step explanation:
because the table is split in to four different tables but it is put together and so the one that is the highest is the first table