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Tamiku [17]
3 years ago
15

Craig just purchased a new car. He financed $45,000 and must pay it back over 5 years with 11% interest. How much will Craig hav

e paid in interest by the time his car is paid off?
Mathematics
1 answer:
Solnce55 [7]3 years ago
8 0

Answer:

$24750

Step-by-step explanation:

Given data

Principal= $45000

Time=5 years

Rate= 11%

Let us apply the simple interest expression

SI= PRT/100

substitute

SI= 45000*11*5/100

SI= 2475000/100

SI= $24750

Hence, Craig would have paid $24750

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Anna35 [415]
11/4 = 2.75
19/8= 2.37

therefore on Wednesday, Alana practiced the closest to 2 hours
3 0
3 years ago
Michelle is cutting string to make necklaces. She has 15 feet of string. She need 1 1/2 feet of string for each necklace. How ma
Degger [83]

Answer:

Number of neckless make = 10

Step-by-step explanation:

Given:

Length of string = 15 ft

Each neckless need = 1\frac{1}{2} = 1.5 ft

Find:

Number of neckless make

Computation:

Number of neckless make = Length of string / Each neckless need

Number of neckless make = 15 / 1.5

Number of neckless make = 10

7 0
2 years ago
How many different 11-letter arrangements can be made using the letters in the word Firecracker?
zhenek [66]

Answer:

Total number of arrangements = 1,663,200

Step-by-step explanation:

Given:

11 - letter

FIRECRACKER

F = 1

I = 1

R = 3

E = 2

C = 2

A =1

K = 1

Find:

Total number of arrangements = ?

Computation:

Note: Repeated letter will be avoid.

Number\ of\  arrangements = \frac{!11}{!3 \times !2 \times !2}\\\\Number\ of\  arrangements = \frac{!11}{!3 \times !2 \times !2} \\\\Number\ of\  arrangements = \frac{11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3}{3 \times 2 \times 2 } \\\\Number\ of\  arrangements = 1,663,200

Total number of arrangements = 1,663,200

6 0
3 years ago
Can somebody help me on 23 and 24, it’s geometry
Luda [366]

Question 23:

x = 4

DE = 44

Question 24:

x = 25

SE = 28

Step-by-step explanation:

As RS is the perpendicular bisector of DE, it will divide DE in two equal parts DS and SE

<u>Question number 23:</u>

Given

DS = 3x+10

SE = 6x-2

As the two segments are equal:

DS = SE\\3x+10 = 6x-2

Subtracting 10 from both sides

3x+10-10 = 6x-2-10\\3x = 6x-12

subtracting 6x from both sides

3x -6x = 6x-6x-12\\-3x = -12

Dividing both sides by -3

\frac{-3x}{-3} = \frac{-12}{-3}\\x = 4

Now

DS = 3x+10\\= 3(4)+10\\= 12+10\\=22

And

SE = 6x-2\\= 6(4)-2\\= 24 - 2\\=22\\DE = DS+SE\\= 22+22\\=44

<u>Question No 24:</u>

Given

DS = x+3

DE = 56

We know that:

DS = \frac{1}{2}DE\\x+3 = \frac{56}{2}\\x + 3 = 28\\x = 28-3\\x = 25

So

DS = 25+3 = 28

As DS is 28, SE will also be 28

Hence,

Question 23:

x = 4

DE = 44

Question 24:

x = 25

SE = 28

Keywords: Bisector, Line segment

Learn more about line segments at:

  • brainly.com/question/629998
  • brainly.com/question/6208262

#LearnwithBrainly

4 0
3 years ago
How do properties of integer exponents help you write equivalent expressions
olga55 [171]

When writing equivalent expressions, there are often several possible orders in which to simplify them. However, they will all take you to the same result as long as you do not make a mistake when using the properties. In this example, you will distribute the outer exponent first using the Power of a Product Property.

7 0
3 years ago
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