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3 years ago

-4(x-1)=-3x+13-9-x Pls do it STEP BY STEP!!

Mathematics

2 answers:

DedPeter [7]3 years ago

8 0

Infinite
That’s
What it
Says

GarryVolchara [31]3 years ago

3 0

Answer:

-4x-4=-4x+4

-4x+4x=4-4

0=0

Step-by-step explanation:

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Prt.3 identify the slope

andreyandreev [35.5K]

Answer:

m = - 2

Step-by-step explanation:

First coordinate : ( -2 , 9 )

Second coordinate : ( 1 , 3 )

Formulae : m=(y2-y1)/(x2-x1)

Substituting,

m = ( 3 - 9 ) / ( 1 + 2 )

m = - 6 / 3

m = - 2

If this helps you, please mark brainliest!

4 0

3 years ago

PLEASE HELP ME I'M GIVING 20PTS AND MARKING BRAINLIEST!!!!

pishuonlain [190]

Using a trigonometric identity, it is found that the values of the cosine and the tangent of the angle are given by:

$\cos{\theta} = \pm \frac{2\sqrt{2}}{3}$

$\tan{\theta} = \pm \frac{\sqrt{2}}{4}$

<h3>What is the trigonometric identity using in this problem?</h3>

The identity that relates the sine squared and the cosine squared of the angle, as follows:

$\sin^{2}{\theta} + \cos^{2}{\theta} = 1$

In this problem, we have that the sine is given by:

$\sin{\theta} = \frac{1}{3}$

Hence, applying the identity, the cosine is given as follows:

$\cos^2{\theta} = 1 - \sin^2{\theta}$

$\cos^2{\theta} = 1 - \left(\frac{1}{3}\right)^2$

$\cos^2{\theta} = 1 - \frac{1}{9}$

$\cos^2{\theta} = \frac{8}{9}$

$\cos{\theta} = \pm \sqrt{\frac{8}{9}}$

$\cos{\theta} = \pm \frac{2\sqrt{2}}{3}$

The tangent is given by the sine divided by the cosine, hence:

$\tan{\theta} = \frac{\sin{\theta}}{\cos{\theta}}$

$\tan{\theta} = \frac{\frac{1}{3}}{\pm \frac{2\sqrt{2}}{3}}$

$\tan{\theta} = \pm \frac{1}{2\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}}$

$\tan{\theta} = \pm \frac{\sqrt{2}}{4}$

More can be learned about trigonometric identities at brainly.com/question/24496175

#SPJ1

5 0

2 years ago

Solve: 2x^2 -x >15 Show your work.

Lyrx [107]

Step by step explanation

6 0

3 years ago

Read 2 more answers

√(112) - √(80) / √(20) - √(28) = ?

Evgesh-ka [11]

$\large\underline{\sf{Solution-}}$

<u>We need to solve,</u>

$\dfrac{\sqrt{112}-\sqrt{80}}{\sqrt{20}-\sqrt{28}}$

We can write the above mentioned expression as,

$\sf\longmapsto\dfrac{\sqrt{2\times2\times2\times2\times7}-\sqrt{2\times2\times2\times5}}{\sqrt{2\times2\times5}-\sqrt{2\times2\times7}}$

So,

$\sf\longmapsto\dfrac{\sqrt{4\times4\times7}-\sqrt{4\times4\times5}}{\sqrt{2^2\times5}-\sqrt{2^2\times7}}$

So,

$\sf\longmapsto\dfrac{\sqrt{4^2\times7}-\sqrt{4^2\times5}}{\sqrt{2^2\times5}-\sqrt{2^2\times7}}$

Hence,

$\sf\longmapsto\dfrac{4\sqrt{7}-4\sqrt{5}}{2\sqrt{5}-2\sqrt{7}}$

Taking common in respective terms,

$\sf\longmapsto\dfrac{4(\sqrt{7}-\sqrt{5})}{2(\sqrt{5}-\sqrt{7})}$

On cancelling 4 with 2,

$\sf\longmapsto\dfrac{4\!\!\!/^{\:2}(\sqrt{7}-\sqrt{5})}{2\!\!\!/(\sqrt{5}-\sqrt{7})}$

$\sf\longmapsto\dfrac{2(\sqrt{7}-\sqrt{5})}{(\sqrt{5}-\sqrt{7})}$

Taking (-) common,

$\sf\longmapsto\dfrac{-2(\sqrt{5}-\sqrt{7})}{(\sqrt{5}-\sqrt{7})}$

So, (√5 - √7) gets cut,

<u>Hence, </u>

$\longmapsto\bf\dfrac{\sqrt{112}-\sqrt{80}}{\sqrt{20}-\sqrt{28}}=-2$

8 0

3 years ago

Josiah's family took a road trip to Mount Rushmore. Josiah fell asleep after they had travelled 174 miles. If the total length o

Serjik [45]

Answer:

Step-by-step explanation:

your welcome

8 0

3 years ago