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Oksana_A [137]
3 years ago
5

Which expression is equivalent to 2*3 / 2^6 A 2^2 B 1/2^2 C 2^8 D 1/2^8

Mathematics
1 answer:
harkovskaia [24]3 years ago
7 0

Answer:

Step-by-step explanation:

B

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Honda Atlas issued 100,000 shares of stock. In 1990, each share of stock was worth Rs. 152.50. In 1993, each share of the stock
noname [10]

Answer:

Rs.13,130 ,000

Step-by-step explanation:

Lets solve first for year 1990

Value of stock in 1990 = Rs. 152.50

No. of stocks issued in 1990 = 100,000

Total value of these stocks in 1990= Value of stock in 1990* no of stocks issued in 1990  = 152.50*100,000 = Rs. 15,250,000

Let solve first for year 1993

Value of stock in 1993 = Rs. 21.20

No. of stocks   1993 = 100,000

Total value of these stocks in 1993 = Value of stock in 1993* no of stocks issued in 1993  = 21.20*100,000 = Rs. 2,120,000

Decrease in value of stock in 1993 in comparison to 1990 = Total value of the stocks in 1990 -Total value of the stocks in 1993

 =  Rs. 15,250,000 - Rs. 2,120,000

 = Rs.13,130 ,000

Thus, the 100,000 shares worth Rs.13,130 ,000 lesser in 1993 than in 1990.

6 0
3 years ago
abby baked 48 cookies and divided them evenly into bags. let b represent the number of bags. write and algebraic expression to r
dybincka [34]
The words literally tell you what to do.
<em>b</em> = the number of bags.

You need to "divide the cookies evenly"

We have "48 cookies".

Now we need to put that together.

48/<em>b</em> is your answer.
<em>
</em><em>Don't forget to rate this answer the Brainliest!</em>


7 0
3 years ago
A trapezoid is a quadrilateral with exactly one pair of parallel sides <br> A) true <br> B)False
Alenkinab [10]
The answer is true to your question
7 0
3 years ago
Read 2 more answers
The distance your car will go with one turn of the wheels.
Gekata [30.6K]
???????? Left or right ???!!!
5 0
3 years ago
If m&lt;1=6x+50 and m&lt;2=4x+40 find x
Pepsi [2]
\text{Adjacent angles on a straight line sum up to 180} \textdegree

\text{Therefore }\measuredangle 1 + \measuredangle 2 = 180 \textdegree

\text {Since } \measuredangle 1 = 6x+50 \text { and } \measuredangle 2 = x+40

(6x+50)  + (4x+40) = 180

6x+50 + 4x+40 = 180

10x+90 = 180

10x = 180 - 90

10x = 90

x = 9

Answer: x = 9
8 0
3 years ago
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