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Norma-Jean [14]
3 years ago
15

N kmjknxcizfdhzkjxfsbvdnkjbchsgnfdb,mfvs cfnbgsuhkjfcbm

Mathematics
1 answer:
kifflom [539]3 years ago
8 0

Answer:

huh thanks for the points ig :)

Step-by-step explanation:

You might be interested in
Compare the numbers by entering <, >, or =.
Andrew [12]
Your answer would be:
596.64 = 596.640
Reasoning= If you just take away the zero from 596.640 you would have the same answer as 596.64. Now if you add a zero to 596.64 you still would have the same answer, therefore they are equal.
Hope this helps! (:
6 0
3 years ago
Find the value of x in each of the given figures.
Kaylis [27]

Answer:

Step-by-step explanation:

1) Given figure is a parallelogram

Area = 144 cm²

base  * altitude = 144

16 * x = 144

x =144/16

x = 9 cm

2)2) Trapezium

Area = \frac{a+b}{2}*h      ; {a and b are parallel sides of trapezium}

( 37 +27 /2) * x  = 480 cm²

64/2 * h = 480

32 *  h = 480

h = 480/32

h = 15 cm

8 0
3 years ago
Rectangle ABCD is similar to rectangle RSTU .
Alenkasestr [34]

Answer:

The scale factor of a dilation from ABCD to RSTU is \frac{1}{2}

Step-by-step explanation:

We know that the rectangle ABCD is similar to rectangle RSTU.

Given that in rectangle ABCD the longest sides are DC and AB and in the rectangle RSTU the longest sides are UT and RS ⇒ The scale factor of a dilation will transform the sides DC and AB into UT and RS

Working with the lengths of the sides :

DC.(Scale factor) = UT

AB.(Scale factor) = RS

Replacing with the values of the lengths (Scale factor : SF) :

DC.SF=UT\\(90ft).(SF)=45ft\\SF=\frac{45ft}{90ft} \\SF=\frac{1}{2}

AB.SF=RS\\(90ft).(SF)=45ft\\SF=\frac{45ft}{90ft} \\SF=\frac{1}{2}

Notice that the scale factor is dimensionless.

We can verify this result with the sides AD and BC :

AD.SF=UR\\50ft.(\frac{1}{2})=25ft\\ 25ft=25ft

BC.SF=TS\\50ft.(\frac{1}{2})=25ft\\ 25ft=25ft

The scale factor (SF) is \frac{1}{2}

7 0
3 years ago
Read 2 more answers
How do you go about simplifying 16/80​
Westkost [7]
16/80 divided by 16 =1/5
6 0
2 years ago
Find a degree 3 polynomial whose coefficient of x^3 equal to 1. The zeros of this polynomial are -5, -4i, and 4i. Simplify your
borishaifa [10]

Answer:

x^3+5x^2+16x+80

Step-by-step explanation:

You know that you can write your polynom this way : (x-r1)(x-r2)(x-r3) with r1,r2 and r3 the roots so you get :

(x+5)(x+4i)(x-4i)

Simplify (x+4i)(x-4i) with the formula (a-b)(a+b)=a²-b²

so you have (x^2+16)=(x+4i)(x-4i)

Your polynom looks like this :

(x^2+16)(x+5) just expand it

and you get x^3+5x^2+16x+80

7 0
2 years ago
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