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xeze [42]
2 years ago
6

Consider the expression

Mathematics
1 answer:
storchak [24]2 years ago
6 0

Answer:

5/6(1/2x)+5/6(6)-3x

-31x/12+5/12-3x

-3x+5/12+5

Step-by-step explanation:

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If you want to make 2 1/2 Batches of cookies and you need one and 1 2/3 cups of flour per cookie batch how much flower do you ne
cupoosta [38]

Answer:

you need 4 1/3 cups of flower

5 0
2 years ago
Find the common ratio for the geometric sequence defined by the formula: an=40(2‾√)n−1 a n = 40 ( 2 ) n − 1
WITCHER [35]

The ratio of the geometric sequence 402^{n-1} is 2.

Given that geometric sequence is 40*2^{n-1} and we have to find the common ratio of all the terms.

Geometric sequence is a sequence in which all the terms have a common ratio.

Nth termof a GP is ar^{n-1} in which a is first term and r is common ratio.

Geometric sequence=40*2^{n-1}

We have to first find the first term, second term and third term of a geometric progression.

First term=40*2^{1-1}

=40*2^{0}

=40*1

=40

Second term=40*2^{2-1}

=40*2^{1}

=40*2

=80

Third term=40*2^{3-1}

=40*2^{2}

=40*4

=160

Ratio of first two terms=80/40=2

Ratio of next two terms=160/80=2

Hence the common ratio of geometric sequence is 2.

Learn more about geometric progression at brainly.com/question/12006112

#SPJ1

4 0
1 year ago
If f(x) = -2(5)*, what is f(2)?
Effectus [21]

Answer:

-2(5)^2

-2(25)

-50

Step-by-step explanation:

7 0
3 years ago
Hew hats the LCM of 6 and 4
Simora [160]
That would be 2 because you can divide both by 2 and get a whole number hope this helps
8 0
3 years ago
Normal distribution HELP
elena-14-01-66 [18.8K]

Answer:

0.0351478382 (To be precise)

Step-by-step explanation: Can I get brainliest? Thanks

1. Normal Distribution --> Z ~ (0,1^2)

2. Use normalcdf(lower bound, upper bound, μ, σ) function on a graphing calculator

P(Z≥103.53) = normalcdf(103.53, 1e99 [default], 80, 13)

P(Z≥103.53) ≈ 0.03

3. μ+σ ≈ 13.59% According to Z-distribution chart

80+13=93

So about 93 exceed only the top 16% (estimated answer not exact)

8 0
2 years ago
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