<span><span><span>1/2</span><span>(<span><span>2g</span>−3</span>)</span></span>=<span>−<span>4<span>(<span>g+1</span>)</span></span></span></span>
<span><span><span>1/2</span><span>(<span><span>2g</span>−3</span>)</span></span>=<span>−<span>4<span>(<span>g+1</span>)</span></span></span></span>
<span><span>g+<span><span>−3/</span>2</span></span>=<span><span>−<span>4g</span></span>−4</span></span>
<span><span><span>g+<span><span>−3/</span>2</span></span>+<span>4g</span></span>=<span><span><span>−<span>4g</span></span>−4</span>+<span>4g</span></span></span><span><span><span>5g</span>+<span><span>−3</span>2</span></span>=<span>−4</span></span>
5g+−3/2+3/2=−4+3/2
<span><span>
5g</span>=<span><span>−5/</span>2</span></span>
<span><span><span>5g/</span>5</span>=<span><span><span>−5</span>2</span>5</span></span><span>
g=<span><span>−1</span><span>2
Hoped I helped!</span></span></span>
Answer:
y = 4/6x - 4
Step-by-step explanation:
y = mx + b, m = slope and b = y intercept
Rise over run
Rise = +4
Run = +6
This means the slope is 4/6.
The y intercept is at -4.
Now, plug in the numbers for y = mx + b
y = 4/6x - 4
5% of 200 is 10, after six months, so total of $60? not sure though.
The constant is 36
because direct variation y/x
Answer:
A) between 7:40 and 7:45
Step-by-step explanation:
Given,
The maximum time taken by her to walk to school = 15 minutes,
Since, the school starts on 8:00 AM,
Also, 15 minutes before 8:00 AM = 7:45 AM,
Thus, the maximum time at which she has to leave home = 7: 45 AM,
Hence, the reasonable estimate of the time she should leave home to get to school by 8:00 is between 7:40 and 7:45.
OPTION A would be correct.
